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Alinara [238K]
3 years ago
5

What’s the rate of change of y=1.5x-2

Mathematics
1 answer:
mars1129 [50]3 years ago
4 0

Answer:

1.5

Step-by-step explanation:

The rate of change is also the slope or m. This equation is in slope intercept form which is y=mx+b. m is the rate of change. m=1.5.

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The Andersons rented 5 rectangular tables for $35 and 30 chairs for $60. Which quotients can be used to calculate the unit cost
stira [4]

Answer:

Step-by-step explanation:

5 tables for 35 bucks.....unit cost is 35/5 = $ 7 bucks per table

30 chairs for 60 bucks...unit cost is 60/30 = $ 2 bucks per chair

5 0
3 years ago
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Given that a=25, b=43 and c=17 solve triangle ABC
Montano1993 [528]
The given lengths cannot form a triangle. They do not meet the requirements of the triangle inequality.

17 + 25 < 43
The triangle inequality requires each side be shorter than the sum of the other two.

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Statistical data can be classified into
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IT CAN BE ORDERED IN THE FORM LOWEST TO HIGHEST BY FOUR LEVELS OF STATISTICS :

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I need help with this
Lady bird [3.3K]
I believe the answer to this is "If they babysit for 5 hours, Jayna will earn more" because Hannah charages 7$ an hour and Jayna charges 10$ an hour so Jayna will have more money than Hannah in five hours. 
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3 years ago
Use the chain rule calculate dw/dr , dw/ds and dw/dt
Liono4ka [1.6K]

Answer:

\frac{dw}{dr} = \frac{8\cdot r}{4\cdot r^{2}-t^{2}+5\cdot s^{2}}, \frac{dw}{ds} = \frac{10\cdot s}{4\cdot r^{2}-t^{2}+5\cdot s^{2}}, \frac{dw}{dt} = -\frac{2\cdot t}{4\cdot r^{2}-t^{2}+5\cdot s^{2}}

Step-by-step explanation:

We proceed to derive each expression by rule of chain. Let be w = \ln (x+2\cdot y + 3\cdot z), x = r^{2}+t^{2}, y = s^{2}-t^{2} and z = r^{2}+s^{2}:

\frac{dw}{dr} = \frac{\frac{dx}{dr}+2\cdot \frac{dy}{dr} +3\cdot \frac{dz}{dr}  }{x+2\cdot y + 3\cdot z}

\frac{dx}{dr} = 2\cdot r

\frac{dy}{dr} = 0

\frac{dz}{dr} = 2\cdot r

\frac{dw}{dr} = \frac{8\cdot r}{(r^{2}+t^{2})+2\cdot (s^{2}-t^{2})+3\cdot (r^{2}+s^{2})}

\frac{dw}{dr} = \frac{8\cdot r}{4\cdot r^{2}-t^{2}+5\cdot s^{2}} (1)

\frac{dw}{ds} = \frac{\frac{dx}{ds}+2\cdot \frac{dy}{ds} +3\cdot \frac{dz}{ds}  }{x+2\cdot y + 3\cdot z}

\frac{dx}{ds} = 0

\frac{dy}{ds} = 2\cdot s

\frac{dz}{ds} = 2\cdot s

\frac{dw}{ds} = \frac{10\cdot s}{(r^{2}+t^{2})+2\cdot (s^{2}-t^{2})+3\cdot (r^{2}+s^{2})}

\frac{dw}{ds} = \frac{10\cdot s}{4\cdot r^{2}-t^{2}+5\cdot s^{2}} (2)

\frac{dw}{dt} = \frac{\frac{dx}{dt}+2\cdot \frac{dy}{dt} +3\cdot \frac{dz}{dt}  }{x+2\cdot y + 3\cdot z}

\frac{dx}{dt} = 2\cdot t

\frac{dy}{dt} = -2\cdot t

\frac{dz}{dt} = 0

\frac{dw}{dt} = -\frac{2\cdot t}{(r^{2}+t^{2})+2\cdot (s^{2}-t^{2})+3\cdot (r^{2}+s^{2})}

\frac{dw}{dt} = -\frac{2\cdot t}{4\cdot r^{2}-t^{2}+5\cdot s^{2}} (3)

7 0
2 years ago
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