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serious [3.7K]
4 years ago
15

Why was it important to let the solution cool down before conducting the titration experiment?

Chemistry
1 answer:
Papessa [141]4 years ago
6 0

Answer:

The pH range, reaction rate, accuracy and solubility are affected by the temperature.

Explanation:

Hello,

Temperature is factor affecting how solutions behave, thus, it could modify the pH range (change in color values) for an indicator in the presence of a base or an acid, since the kinetics behind the change of color is modified maybe decreasing or increasing the aforesaid range. Next, temperature usually increases the reaction rate, that's why the change in color could become faster or out of the proper change range. Then, in titration we use temperature-sensitive glassware which could expand due to high temperatures and subsequently turning out into wrong measurements. Finally, solubility is affected by the temperature, since the molecules are allowed to interact more effectively, that's we must make sure that they're completely dissolved at room temperature while titrating.

Best regards.

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Consider the following system at equilibrium:D(aq)+E(aq)<=>F(aq)Classify each of the following actions by whether it cause
igomit [66]

Explanation:

D(aq) + E(aq) <=> F(aq)

This question is based on Le Chatelier's principle.

Le Chatelier's principle is an observation about chemical equilibria of reactions. It states that changes in the temperature, pressure, volume, or concentration of a system will result in predictable and opposing changes in the system in order to achieve a new equilibrium state.

Increase D

D is a reactant. if we add reactants to the system, equilibrium will be shifted to the right to in order to maintain equilibrium by producing more products.

Increase E

E is a reactant. if we add reactants to the system, equilibrium will be shifted to the right to in order to maintain equilibrium by producing more products.

Increase F

F is a product.  If we add additional product to a system, the equilibrium will shift to the left, in order to produce more reactants. The reaction would shift to the left.

Decrease D

if we remove reactants from the system, equilibrium will  be shifted to the left.

Decrease E

if we remove reactants from the system, equilibrium will  be shifted to the left.

Decrease F

if we remove products from the system, equilibrium will be shifted to the right to in order to maintain equilibrium by producing more products.

Triple D and reduce E to one third

no shift in the direction of the net reaction, Both changes cancels each other.

Triple both E and F

no shift in the direction of the net reaction, Both changes cancels each other.

4 0
4 years ago
For the oxidation of glucose (C6H12O6 + 6O2 --&gt; 6H20 + 6CO2), how many grams of oxygen gas will be consumed when 950g of gluc
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You need to find the mole of glucose by using the formula n = m/Mr. Once you have found the mole you need to follow the stoichiometric process by unknown/known using the co-efficients. Then you need to multiple your answer by the known mole of glucose whoch you have previously calculated. After that you should get the mole of oxygen then you just need to transpose the equation to get m = n×Mr, substitute ypur answers in, remebering you can find your Mr via the period table, you have your answer
4 0
4 years ago
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A chemist can determine the mass of K in a sample of known mass that consists of either pure K2O or pure K2O2. From this informa
Arte-miy333 [17]

Yes , the chemist can answer if the compound in K2O or K2O2

The chemical formula and composition of both the compounds is entirely different. The compound K2O2 has an additional molecule of oxygen than K2O and hence will have have higher molecular mass.

In the compound K2O

molecular mass= 2x 39+16 =94

mass ratio of K in compound= 78/94 = 0.830

In the compound K2O2

molecular mass= 2x 39+16X2 =110

mass ratio of K in compound= 78/110 = 0.710

and hence by the required ratio while extracting K , the chemist may know if the compound is K20 or K2O2

If the ratio is anything different from 0.830 and 0.710 then the compund will be something different

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5 0
2 years ago
Find an expression for the change in entropy when two blocks of the same substance of equal mass, one at the temperature Th and
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Explanation:

Relation between entropy change and specific heat is as follows.

            \Delta S = C_{p} log (\frac{T_{2}}{T_{1}})

The given data is as follows.

     mass = 500 g,         C_{p} = 24.4 J/mol K

     T_{h} = 500 K,          T_{c} = 250 K               

   Mass number of copper = 63.54 g /mol

Number of moles = \frac{mass}{/text{\molar mass}}

                                 = \frac{500}{63.54}

                                 = 7.86 moles

Now, equating the entropy change for both the substances as follows.

     7.86 \times 24.4 \times [T_{f} - 250] = 7.86 \times 24.4 \times [500 -T_{f}]

       T_{f} - 250 = 500 - T_{f}

          2T_{f} = 750

So,       T_{f} = 375^{o}C

  • For the metal block A,  change in entropy is as follows.

         \Delta S = C_{p} log (\frac{T_{2}}{T_{1}})

              = 24.4 log [\frac{375}{500}]

              = -3.04 J/ K mol

  • For the block B,  change in entropy is as follows.

         \Delta S = C_{p} log (\frac{T_{2}}{T_{1}})

                  = 24.4 log [\frac{375}{250}]

                  = 4.296  J/Kmol

And, total entropy change will be as follows.

                       = 4.296 + (-3.04)

                      = 1.256 J/Kmol

Thus, we can conclude that change in entropy of block A is -3.04 J/ K mol  and change in entropy of block B is 4.296  J/Kmol.

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Habitat destruction of the ecosystem.
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