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serious [3.7K]
4 years ago
15

Why was it important to let the solution cool down before conducting the titration experiment?

Chemistry
1 answer:
Papessa [141]4 years ago
6 0

Answer:

The pH range, reaction rate, accuracy and solubility are affected by the temperature.

Explanation:

Hello,

Temperature is factor affecting how solutions behave, thus, it could modify the pH range (change in color values) for an indicator in the presence of a base or an acid, since the kinetics behind the change of color is modified maybe decreasing or increasing the aforesaid range. Next, temperature usually increases the reaction rate, that's why the change in color could become faster or out of the proper change range. Then, in titration we use temperature-sensitive glassware which could expand due to high temperatures and subsequently turning out into wrong measurements. Finally, solubility is affected by the temperature, since the molecules are allowed to interact more effectively, that's we must make sure that they're completely dissolved at room temperature while titrating.

Best regards.

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Read 2 more answers
What is the ph of a solution of 0.550 m k2hpo4, potassium hydrogen phosphate?
Solnce55 [7]
We assume that we have Ka= 4.2x10^-13 (missing in the question)
and when we have this equation:
H2PO4 (-) → H+  + HPO4-
and form the Ka equation we can get [H+]:
Ka= [H+] [HPO4-] / [H2PO4] and we have Ka= 4.2x10^-13 & [H2PO4-] = 0.55m
by substitution:
4.2x10^-13 = (z)(z)/ 0.55
z^2 = 2.31x 10^-13
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∴[H+] = 4.81x10^-7
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3 0
3 years ago
A star is estimated to have a mass of 2.0 x 10 ^36kg. Assuming it to be a sphere of average radius of 7.0 x 10 ^5 km. Calculate
Montano1993 [528]

Answer:

<em>a)</em> <em>1.392 x 10^6 g/cm^3</em>

<em>b) 8.69 x 10^7 lb/ft^3</em>

<em></em>

Explanation:

mass of the star m =  2.0 x 10^36 kg

radius of the star (assumed to be spherical) r = 7.0 x 10^5 km = 7.0 x 10^8 m

The density of substance ρ = mass/volume

The volume of the star = volume of a sphere = \frac{4}{3}\pi  r^{3}

==> V = \frac{4}{3}*3.142*(7.0*10^8)^{3} = 1.437 x 10^27 m^3

density of the star ρ = (2.0 x 10^36)/(1.437 x 10^27) = 1.392 x 10^9 kg/m^3

in g/cm^3 = (1.392 x 10^9)/1000 = <em>1.392 x 10^6 g/cm^3</em>

in lb/ft^3 =  (1.392 x 10^9)/16.018 = <em>8.69 x 10^7 lb/ft^3</em>

6 0
3 years ago
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