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son4ous [18]
3 years ago
12

When carbon is burned in air, it reacts with oxygen to form carbon dioxide. When 24.0 g of carbon were burned in the presence of

82.7 g of oxygen, 18.7 g of oxygen remained unreacted. What mass of carbon dioxide was produced?
Chemistry
1 answer:
Novosadov [1.4K]3 years ago
8 0

Answer:

mass of CO2 = 88 g

Explanation:

It is stated in question that 18.7 g of oxygen remained unreacted which means that carbon is limiting reactant. Thus the amount of carbon dioxide produced depend upon the amount of carbon.

Given data:

mass of carbon = 24 g

total mass of oxygen 82.7 g

mass of unreacted oxygen = 18.7 g

mass of carbon dioxide = ?

Solution:

First of we will calculate the moles of carbon.

number of moles of carbon = mass of carbon / atomic weight

number of moles of carbon = 24 g/ 12 g/mol = 2 mol

Chemical equation:

C + O2 → CO2

now we compare the number of moles of carbon and carbon dioxide,

  C   :  CO2

  1    :    1

 2    :    2

Now we will calculate the mass of carbon dioxide from moles.

number of moles of CO2 = mass of CO2 / molar mass of CO2

2 mol × 44 g/mol = mass

mass of CO2 = 88 g

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How many grams hydrogen in 4.5 mol H2SO4
swat32
H2SO4 ---> 2H^+ + SO4^2-

Hence n H+ = 9 mols

Mass of H = nM = (9*1) = 9g


Alternately

mass of H2SO4= nM= 4.5*98= 441

Mass of H= mass h2so4 * molar mass of H/molar mass of h2so4
Mass of H= 441 * 2/98 = 9g

4 0
3 years ago
A substance that is ______ will NOT dissolve in a solvent. A) freezing B) insoluble C) evaporating D) soluble
Alexxandr [17]

Answer:

insoluble

Explanation:

4 0
3 years ago
Read 2 more answers
1. If 335g water at gains 1,666.11 J of heat, how much does the temperature of the
Setler79 [48]

Answer:

Explanation:

cold and hot are temperatures

4 0
2 years ago
Which of these, if dissolved in 1.0 l of pure water, would produce a buffer solution? which of these, if dissolved in 1.0 l of p
stiks02 [169]

Answer:

  1. (0.1 mol NaH₂PO₄ + 0.1 mol Na₂HPO₄)

Explanation:

A buffer solution is an aqueous solution consisting of a mixture of a weak acid and its conjugate base, or weak base and its conjugate acid.

Also, a buffer solution is a solution which resists changes in pH when acid or alkali is added to it.

  1. (0.1 mol NaH₂PO₄ + 0.1 mol Na₂HPO₄) when dissolved in 1 L H₂O will produce a buffer because NaH₂PO₄ is considered as weak acid while Na₂HPO₄ is its conjugate base. 2.
  2. (0.1 mol H₃O⁺ + 0.1 mol Cl⁻) is not a mixture of a weak acid and its conjugate base, or weak base and its conjugate acid.
  3. (0.1 mol HCl + 0.1 mol NaoH) HCL is a strong acid and NaOH is a strong base so it will not form a buffer when dissolved in water.
  4. (0.1 mol H₃O⁺ + 0.1 OH⁻) is not a mixture of a weak acid and its conjugate base, or weak base and its conjugate acid
  5. (0.1 mol NaCl+ 0.1 mol KCl) NaCL and KCL are salts so it will not form a buffer when dissolved in water.

So the right choice is

  1. (0.1 mol NaH₂PO₄ + 0.1 mol Na₂HPO₄)

7 0
3 years ago
A wave has a frequency of 3,5MHz and a wavelength of 85,5 m. What is the wave velocity through
Yuki888 [10]

Answer:

velocity = 29925×10⁶ m/s

Explanation:

Given data:

Frequency = 35 MHz

Wavelength = 855 m

Velocity = ?

Solution:

MHz to Hz

35×10⁶ Hz

Formula:

<em>velocity = Wavelength × Frequency</em>

velocity = 855 m × 35×10⁶ Hz

velocity = 29925×10⁶ m/s

Hz = s⁻¹

5 0
3 years ago
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