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Savatey [412]
3 years ago
14

What is Napoleon's friend's name? From the Napoleon Dynamite movie.

Computers and Technology
1 answer:
Setler79 [48]3 years ago
3 0

Answer:

Pedro

Explanation:

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List the data types that are allowed for SQL attributes.
nalin [4]

Answer:

Explanation:

In the SQL database manipulation coding language, there are a variety of different available data types to use. These data types are the following.

  • Numeric
  • Date/Time
  • Character/String
  • Unicode Character/String
  • Binary
  • 3rd Party / Miscellaneous

Each of these data types has a wide range of subcategories (data types as well) that each handle different variables in a coding sequence. These subcategories can be all seen in the attached picture below.

6 0
3 years ago
// This pseudocode is intended to describe
ddd [48]

Applying given information of a computational language in pseudocode, a code may be written to represent computing the price of an item on sale for 10% off.

<h3>What is a pseudocode?</h3>

A pseudocode can be considered as a depiction of the steps represented in an algorithm, usually in plain (natural) language.

<em>//This </em><em>pseudocode </em><em>is intended to describe</em>

<em>//computing the </em><em>price </em><em>of an </em><em>item </em><em>on </em><em>sale </em><em>for 10% off</em>

<em>START</em>

<em>  input origPrice</em>

<em>  </em><em>discount </em><em>= origPrice * 0.10</em>

<em>  </em><em>finalPrice </em><em>= origPrice - discount</em>

<em>  output finalPrice</em>

<em>STOP</em>

<em>//This pseudocode is intended to </em><em>compute </em><em>the number</em>

<em>//of miles per </em><em>gallon </em><em>you get with your car.</em>

<em>START</em>

<em>  input milesTraveled</em>

<em>  input gallonsOfGasUsed</em>

<em>  milesPerGallon = milesTraveled / gallonsOfGasUsed</em>

<em>     //milesPerGallon is computed using </em><em>division</em>

<em>  output milesPerGallon</em>

<em>     //miles is misspelled, and the P in </em><em>milesPerGallon </em><em>should be uppercase</em>

<em>STOP</em>

<em>  //</em><em>Program </em><em>should end with stop</em>

<em>//This pseudocode is intended to describe</em>

<em>//computing the </em><em>per day cost </em><em>of your rent</em>

<em>//in a 30-day month</em>

<em>START</em>

<em>  input rent</em>

<em>  costPerDay = rent / 30</em>

<em>     // Comment indicates 31-day month</em>

<em>  output costPerDay</em>

<em>     // output should be </em><em>costPerDay</em>

<em>STOP</em>

Learn more about the pseudocode here :

brainly.com/question/13208346

#SPJ1

3 0
1 year ago
Create a Rational number class in Java using the same style as the Complex number class created in class.(The in class example c
Elis [28]

Answer:

Explanation:

/*

*    This program adds, subtracts, multiplies, and divides two rational numbers.

*/

public class Main {

  //Main method

   public static void main(String[] args) {

       Rational a = new Rational(3, 4);   // input for first rational number

       Rational b = new Rational(2 , 5);   // input for second rational number

       System.out.println(a + " + " + b + " = " + a.add(b));

       System.out.println(a + " - " + b + " = " + a.sub(b));

       System.out.println(a + " * " + b + " = " + a.mul(b));

       System.out.println(a + " / " + b + " = " + a.div(b));

   }

}

class Rational {

   public Rational(int num, int den) {

      numerator = num;

      denominator = den;

     

      //ensures a non-zero denominator

      if (den == 0)

          den =1;

     

      //stores a negative sign in numerator

      if (den < 0) {

          num = num * -1;

          den = den * -1;

      }

   }

   //return numerator

   public int getNumerator() {

     

      return numerator;

   }

 

   //return denominator

   public int getDenominator() {

     

      return denominator;

   }

 

   //return reciprocal method

   public Rational reciprocal() {

     

      return new Rational(denominator, numerator);

   }

   /*   Addition Class

    *        Find common denominator by multiplying the denominators

    *        Store number values (numerator / common denominator) as num1 and num2

    *        Sum both numbers

    */

   public Rational add(Rational r2) {

      int comDen = denominator * r2.getDenominator();

      int num1 = numerator * r2.getDenominator();

      int num2 = r2.getNumerator() * denominator;

      int sum = num1 + num2;

      return new Rational (sum, comDen);

   }

   //Subtraction Class - same implementation as Addition Class

   public Rational sub(Rational r2) {

   

     int comDen = denominator * r2.getDenominator();

     int num1 = numerator * r2.getDenominator();

     int num2 = r2.getNumerator() * denominator;

     int difference = num1 - num2;

     return new Rational (difference, comDen);

  }

   

  /*   Multiplication Class

   *        Multiply numerator with r2 numerator

   *        Multiply denominator with r2 denominator

   */

  public Rational mul(Rational r2) {

   

     int num = numerator * r2.getNumerator();

     int den = denominator * r2.getDenominator();

     return new Rational (num, den);

  }

  /*   Divide Class

   *        Multiply number by r2 reciprocal

   */

  public Rational div(Rational r2) {

      return mul (r2.reciprocal());

  }

  /*   toString Method

   *        Returns rational number as a string - in parenthesis if a fraction

   */

  public String toString() {

     

      return (((numerator == 0) ? "0" : ( (denominator == 1) ? numerator + "": "(" + numerator + "/" + denominator + ")")));

 

      /* Logic for toString method

      * if (num == 0) {

              return "0";

          } else {

              if (denominator == 1){

                  return numerator;

              } else {

                  return numerator + "/" + denominator;

              }

      */

   }

  // Declare variables

  private int numerator, denominator;

 

}

output

(3/4) + (2/5) = (23/20)                                                                                                                                      

(3/4) - (2/5) = (7/20)                                                                                                                                      

(3/4) * (2/5) = (6/20)                                                                                                                                      

(3/4) / (2/5) = (15/8)                                                                                                                                      

6 0
3 years ago
During boom times, which of the
pashok25 [27]
I think the answer is D.
3 0
3 years ago
____________improves the understandability of a website, by maintaining similar design elements throughout.
lora16 [44]

Simple and easy user interface design can help the users understand what they can do on the website, without confusion when they are loading on the website.

Best practice on the users experiences can help the users to visit the website easily and get what they want as fast as possible. It is the way to improve a website understandability.

4 0
3 years ago
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