If it stores any type of objects mixed, use Object as storage class. All classes inherit from Object and for primitives use their respective wrapper classes. Or just use one of the bazillion container classes that already exist.
Answer:
A concern that might be expressed by the legal department after reviewing the SLAs and terms of service is:
c. Ensuring that there is a guarantee that the cloud service provider will provide notice in the event that they decide to discontinue operations.
Explanation:
The SLA that the legal department will review should include a description of the services to be provided, expected service levels, measurement metrics for each service, each party's duties and responsibilities, and the contract remedies or penalties for breach, among others. But the legal department will be mostly concerned with legal remedies during breaches, liability limitation and warranties, and intellectual property protection issues than with more technical issues. This is despite the fact that all the terms of the SLA will be diligently reviewed by the legal department.
Answer:
See the code below and the algorithm explanation on the figure.
Explanation:
The explanation in order to get the answer is given on the figure below.
Solving this problem with C. The program is given below:
#include <stdio.h>
int main(void) {
int n, Even=0, Odd=0, Zeros=0;
for (;;) {
printf("\nEnter the value the value that you want to check(remember just integers): ");
//IF we input a non-numeric character the code end;
if (scanf("%d", &n) != 1) break;
if (n == 0) {
Zeros++;
}
else {
if (n % 2) {
Even++;
}
else {
Odd++;
}
}
}
printf("for this case we have %d even, %d odd, and %d zero values.", Even, Odd, Zeros);
return 0;
}
Answer:
There are no statements in the question, so I explained the whole code.
Explanation:
A map consists of key - value pairs. The put method allows you to insert values in the map. The first parameter in the put method is the key, and the second one is the value. Also, the keys must be unique.
For example, map.put("123", "John Smith"); -> key = 123, value = John Smith
Even though the key 123 is set to John Smith at the beginning, it will have the updated value Steve Yao at the end. That is because the keys are unique.
Note that the key 222 also has Steve Yao for the value, that is totally acceptable.
Tape a spoiler to the trunk.
