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Anastasy [175]
4 years ago
13

To make 5 pies,need about 2 pounds of apples.h ow many pounds do you need to make 20 apple pies?

Mathematics
2 answers:
otez555 [7]4 years ago
4 0
You can solve this by cross multiplying. Set up two ratios of how many pounds of apples over how many pies.

\frac{2}{5} = \frac{x}{20}   Cross-multiply
5x = 2 (20)   Multiply
5x = 40        Divide
x = 8

You need 8 pounds of apples to make 20 pies.
ryzh [129]4 years ago
4 0
10 pounds
20 apple pie x 2 pounds=10 pounds
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saveliy_v [14]





As a general rule, a percentage can be converted to a decimal fraction by dividing the given percentage by 100%.

63 1/3%  is equivalent to 190/3% .  Dividing this by  100%, we get 190/300, or 19/30.

63 1/3% of 60 is what?  To determine this, multiply 60 by 19/30.  That comes out to (60)(19)/30, or 2(19), or 38 (answer).
5 0
3 years ago
-7p-4>26p-94 what is p
fenix001 [56]

Answer: p < \dfrac{30}{11}

<u>Step-by-step explanation:</u>

-7p - 4 > 26p - 94

<u>+7p     </u>     <u>+7p          </u>

       -4 >  33p - 94

<u>     +94 </u>    <u>       +94   </u>

     90 >  33p

<u>    ÷33</u>   <u> ÷33  </u>

     \dfrac{90}{33}>p

\large\boxed{p

7 0
3 years ago
Jelly's Candy Shop sells jelly beans by weight. They charge $8.95 per pound. You and your date each filled a bag with jelly bean
Vaselesa [24]

Answer:$9.49

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4 0
3 years ago
Read 2 more answers
Which of the following numbers is between 0.40 and 0.47 ?
fredd [130]

The Answer is 21/50 which is = 0.42

6 0
3 years ago
Read 2 more answers
PLS HELP DUE TODAY
Gekata [30.6K]

Here we go !!

Since it's a regular pentagon, all it's sides are equal so let's solve for x

\hookrightarrow \: 3(x - 1)  = 5x - 6

\hookrightarrow \: 3x - 3 = 5x - 6

\hookrightarrow \:  3x - 5x =  - 6 + 3

\hookrightarrow \:  - 2x =  - 3

\hookrightarrow \: x =  \dfrac{ - 3}{ - 2}

\boxed{\boxed{x =  \dfrac{3}{2} }}

now let's find the measure of each side, i.e

\hookrightarrow \: 5x - 6

\hookrightarrow \: (5 \times  \dfrac{3}{2})  - 6

\hookrightarrow \:  \dfrac{15}{2}   - 6

\hookrightarrow \: 7.5 - 6

\mathrm{\hookrightarrow \: 1.5 \: units}

perimeter = 5 × side length ( for a regular pentagon )

\hookrightarrow \: 1.5 \times 5

\boxed{ \boxed{ \:  \:  \:  \:  \:  \:  \:  \: 7.5 \:  \:  units \:  \:  \:  \:  \:    \:  \:  }}

6 0
3 years ago
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