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3 years ago

6

63 1/3% of 60 is what

1 answer:

saveliy_v [14]3 years ago

5 0

As a general rule, a percentage can be converted to a decimal fraction by dividing the given percentage by 100%.

63 1/3% is equivalent to 190/3% . Dividing this by 100%, we get 190/300, or 19/30.

63 1/3% of 60 is what? To determine this, multiply 60 by 19/30. That comes out to (60)(19)/30, or 2(19), or 38 (answer).

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Can you help me with my Math, please?

creativ13 [48]

The first poster is not an accurate representation of the painting, but the second poster is an accurate representation because the ratio between the first and original lengths did not equal the ratio between the first and original widths but the second poster's ratios were equal.

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3 years ago

Read 2 more answers

Showing ALL calculations, whether this statement is valid

choli [55]

Answer:

<em>R</em><em>M</em>79 608.51

Step-by-step explanation:

First year,

<em>RM</em>505 050.00×5%=<em>RM</em>505 050.00×5/100

=<em>RM</em>25 252.50

second year,

(<em>RM</em>505 050.00+<em>R</em><em>M</em>25 252.50)×5%=<em>RM</em>530 302.50×5/100

=<em>RM</em>26 515.13

third year,

(<em>R</em><em>M</em>530 302.50+<em>R</em><em>M</em>26 515.13)×5%=<em>R</em><em>M</em>556817.63×5/100

=<em>R</em><em>M</em>27840.88

three years interest,

<em>RM</em>25 252.50+<em>RM</em>26 515.13+<em>RM</em>27840.88=<em>RM</em>79608.51

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8 0

3 years ago

When do you carry the high number in vertical multiplication

tangare [24]

When it is greater than 9.

Example

15
x 5
——-

5x5 is 25, so you would leave 5 and carry the 2

2
15
x. 5
——-
5

3 0

3 years ago

3х - 2y = 12<br> x + y = 4

EastWind [94]

4,0

that is the ordered pair of the solution:)

5 0

3 years ago

A linear sequence starts a+3b a+7b a+11b the 2nd term has value 19 the 5th term has value 67 work out the values of a and b

alekssr [168]

Answer:

$a = -9$

$b = 4$

Step-by-step explanation:

Given

Sequence: a+3b, a+7b, a+11b

2nd term = 19

5th term = 67

Required

Find a and b

First, the 5th term needs to be calculated;

Using formula for Arithmetic Progression (AP), the formula goes thus

$T_n = T_1 + (n - 1)d$

Where n = 5

T_1 = a + 3b ------------ FIrst term

$d = T_2 - T_1 or T_3 - T_2$ --- Difference between two successive terms

$d = a + 7b - (a + 3b)$

$d = a + 7b -a - 3b$

$d = a - a + 7b - 3b$

$d = 4b$

So, $T_n = T_1 + (n - 1)d$ becomes

$T_5 = a + 3b + (5 - 1)4b$

$T_5 = a + 3b + (4)4b$

$T_5 = a + 3b + 16b$

$T_5 = a + 19b$

Now that we have values for 2nd and 5th term;

From the second, T2 = 19 and T5 = 67

This gives

$a + 7b = 19$ --- Equation 1

$a + 19b = 67$ ---- Equation 2

Make a the subject of formula in (1)

$a = 19 - 7b$

Substitute these values in equation 1

$a + 19b = 67$ becomes

$19 - 7b + 19b = 67$

$19 + 12b = 67$

Collect like terms

$12b= 67 - 19$

$12b = 48$

Divide both sides by 12

$\frac{12b}{12} = \frac{48}{12}$

$b = 4$

Recall that b = 4

Substitute a = 19 - 7b and nothing will hire

$a = 19 - 7(4)$

$a = 19 - 28$

$a = -9$

Hence, the values of a and b are -9 and 4 respectively.

5 0

3 years ago