Step-by-step explanation:
a.
2(3x) - 5x = 4
6x - 5x = 4
x = 4
B. -5(x-4)+8x=29
-5x+20+8x=29
3x+20=29
3x=9
x=3
C. 2y=18+2(3-y)
2y=18+6-2y
2y=24-2y
4y=24
y=6
D. c = -b - 11
3c + 6 = 6b
3( -b - 11) +6 = 6b
-3b-33+6=6b
-3b-27=6b
-27=9b
3=b
Use the remainder theorem: we can decompose the given polynomial in terms of quotient and remainder polynomials 
and 
, respectively, such that
Then letting x = -3 makes the quotient term vanish, and we're left with a remainder of
So b=-2 so you plug b in
l(-2)l + (-2)^3.
The absolute value of -2 is just 2 so now it is
2 + (-2)^3.
-2 * -2 is 4 but 4 * -2 is -8. So 2 + (-8) or 2 - 8 which comes to equal (-6) or negative six.
In order to solve this sentence you must make terms out of the words. Answer: 1 + (1x)
