12, 2, 4, and 7. The coefficients in the expression 12xy³+2x⁵y+4x⁵y²+7x⁵y are 12, 2, 4, and 7.
In order to solve this problem we have to know that the coefficients is a factor linked to a monomial. For example, the first monomial of the equation is 12xy³ the coeffcient of xy³ is 12.
Answer:
4
Step-by-step explanation:
7x = x² - 8
=> x² - 7x - 8 = 0
use quadratic formula:
a = 1, b = -7, c = -8
x = 
<em>(pls ignore the "A" I don't know why it's showing up)</em>
=> x = 
=> x = 
=> x = 
= 4 or 
= -5 <em>(the answer is only 4 since it's asking for the positive solution)</em>
Answer:
ok then
Step-by-step explanation:
gooood............
Answer:
y = 6 so
2x + 3y = 36y is equal to:
2x + 3*6 = 36*6
-> 2x + 18 = 216
We must now move 18 to the other side of the equation. As we do that, we also change it's sign to negative 18:
2x = 216 - 18
We simplify this
2x = 198
Now, that we got to this point, we know that 2x is equal to 198. To find x we must divide the both sides of the equation by two:
2x/2 = 198/2
And we get that
x = 99
Step-by-step explanation:
•Given 7 - 8 = -1
• -[-7 + 8] = -1, This choice
• 0 - 7 + (-8) = -15
• 7? + -8 = -1, This choice (if I understand “07” correctly)
• -7 + 8 = 1
