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2 years ago

15

Which type of correlation would you expect to see between the weight added to a barbell and the number of times that barbell is

lifted?
A.positive correlation
B.negative correlation
C.no correlation

2 answers:

Stolb23 [73]2 years ago

4 0

Answer:

B negative.

Step-by-step explanation:

andreyandreev [35.5K]2 years ago

4 0

Answer:

Step-by-step explanation:

its negative got ut correct on my quiz

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5(x-2)-3= 5x-13<br>help me plz

Anna007 [38]

X has infinity solutions.

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2 years ago

Chris is reading a book that has nine-hundred seventy-eight pages in it. Every night

GaryK [48]

9514 1404 393

Answer:

Every night

Step-by-step explanation:

The problem statement tells you ...

"Every night Chris reads a number of pages that can be rounded to the nearest hundred."

Then it asks you ...

"On what nights does Chris read a number of pages that can be rounded to the nearest hundred?"

If we take the problem statement at face value, the answer must be ...

"Every night."

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2 years ago

I will make brainiest if you answer correctly!!!<br>What is the difference between a human and a dog

KonstantinChe [14]

Dogs walk on 4 legs.

Dogs have a stronger smell than us.

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3 0

3 years ago

The probability that event M will not occur is 0.8 and the probability that event R will not occur is 0.6. If events M and R can

ololo11 [35]

Answer:

11/25 The right answer is not a part of the options given.

Step-by-step explanation:

Given;

Probability that event M will not occur = 0.8

Probability that event R will not occur = 0.6

Then the ;

Probability that event M will occur = 1 - 0.8 = 0.2

Probability that event R will occur = 1 - 0.6 = 0.4

If events M and R cannot both occur, probability that either event M or event R will occur

= probability that M occurs and R does not or the probability that R occurs and M does not

= 0.2 × 0.6 + 0.4 × 0.8

= 0.12 + 0.32

= 0.44

= 11/25

6 0

3 years ago

Recorded here are the germination times (in days) for ten randomly chosen seeds of a new type of bean. See Attached Excel for Da

alexgriva [62]

Answer:

The 99% confidence interval for the mean germination time is (12.3, 19.3).

Step-by-step explanation:

<em>The question is incomplete:</em>

<em>Recorded here are the germination times (in days) for ten randomly chosen seeds of a new type of bean: 18, 12, 20, 17, 14, 15, 13, 11, 21, 17. Assume that the population germination time is normally distributed. Find the 99% confidence interval for the mean germination time.</em>

<em />

We start calculating the sample mean M and standard deviation s:

$M=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M=\dfrac{1}{10}(18+12+20+17+14+15+13+11+21+17)\\\\\\M=\dfrac{158}{10}\\\\\\M=15.8\\\\\\$

$s=\sqrt{\dfrac{1}{n-1}\sum_{i=1}^n\,(x_i-M)^2}\\\\\\s=\sqrt{\dfrac{1}{9}((18-15.8)^2+(12-15.8)^2+(20-15.8)^2+. . . +(17-15.8)^2)}\\\\\\s=\sqrt{\dfrac{101.6}{9}}\\\\\\s=\sqrt{11.3}=3.4\\\\\\$

We have to calculate a 99% confidence interval for the mean.

The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.

The sample mean is M=15.8.

The sample size is N=10.

When σ is not known, s divided by the square root of N is used as an estimate of σM:

$s_M=\dfrac{s}{\sqrt{N}}=\dfrac{3.4}{\sqrt{10}}=\dfrac{3.4}{3.162}=1.075$

The degrees of freedom for this sample size are:

df=n-1=10-1=9

The t-value for a 99% confidence interval and 9 degrees of freedom is t=3.25.

The margin of error (MOE) can be calculated as:

$MOE=t\cdot s_M=3.25 \cdot 1.075=3.49$

Then, the lower and upper bounds of the confidence interval are:

$LL=M-t \cdot s_M = 15.8-3.49=12.3\\\\UL=M+t \cdot s_M = 15.8+3.49=19.3$

The 99% confidence interval for the mean germination time is (12.3, 19.3).

8 0

3 years ago