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Bogdan [553]
3 years ago
10

Evaluate C(7,3) A.) 4 B.) 35 C.) 70

Mathematics
2 answers:
Sedbober [7]3 years ago
7 0

Answer:

35, is your answer my friend

butalik [34]3 years ago
6 0

Answer:

math

way

.com

Step-by-step explanation:

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Help!! on question 13, solve each equation for x.
GaryK [48]
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5 0
3 years ago
Find dy/dx for 4 - xy = y^3
storchak [24]

Answer:

\frac{dy}{dx}=-\frac{y}{3y^2+x}

Step-by-step explanation:

4-xy=y^3

dy/dx=?

\frac{d(4-xy)}{dx}=\frac{d(y^3)}{dx}\\ \frac{d(4)}{dx}-\frac{d(xy)}{dx}=3y^{3-1}\frac{dy}{dx}\\ 0-(\frac{dx}{dx}y+x\frac{dy}{dx})=3y^2\frac{dy}{dx}\\ -(1y+x\frac{dy}{dx})=3y^2\frac{dy}{dx}\\ -(y+x\frac{dy}{dx})=3y^2\frac{dy}{dx}\\ -y-x\frac{dy}{dx}=3y^2\frac{dy}{dx}

Solving for dy/dx: Addind x dy/dx both sides of the equation:

-y-x\frac{dy}{dx}+x\frac{dy}{dx}=3y^2\frac{dy}{dx}+x\frac{dy}{dx} \\ -y=3y^2\frac{dy}{dx}+x\frac{dy}{dx}

Common factor dy/dx on the right side of the equation:

-y=(3y^2+x)\frac{dy}{dx}

Dividing both sides of the equation by 3y^2+x:

\frac{-y}{3y^2+x}=\frac{(3y^2+x)}{3y^2+x}\frac{dy}{dx}\\ -\frac{y}{3y^2+x}=\frac{dy}{dx}\\ \frac{dy}{dx}=-\frac{y}{3y^2+x}

7 0
3 years ago
What will the answer be
PSYCHO15rus [73]
Since 1 is your initial value you plot a point at (0,1) just like you did , but since your slope (rise/run) is 3, you will go up 3 and over 1, so you will need to graph the point (1,4) instead of (1,-2). Your line will be going up , since a graph is read left to right, you have a positive slope so your line will go up. Hope I helped !
8 0
3 years ago
Read 2 more answers
Answer the photo below thanks
Ad libitum [116K]

Answer:

6x60=360

Step-by-step explanation:

60

6 0
3 years ago
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