Answer:
Step-by-step explanation:
All other things being equal (and there are a lot of other things) the 50 gram mass will show a larger temperature
increase than the 100 gram mass.
Why?
The formula is the same from both masses of water (50 grams and 100 grams)
The amount of heat added is the same. (Instead of using hot water, we'll a hot plate on a very low temperature but above what they are now.).
We'll leave it on until we see a rise in temperature delta(t1) = 10 degrees
mc delta(t) = m1 * c * delta(t1)
m = 100
m1 = 50 grams.
c is going to be divided out
we'll solve for the ratio of delta(t) / delta(t1)
100 * delta(t) = 50 (delta(t1)
100 * delta(t) = 50*10
delta(t) = 50*10/100
delta(t) = 5 degrees.
Though this may look rather convoluted, the result is telling us is that delta(t1) for the 50 gram mass is twice as big as as for the 100 gram mass.
The 100 gram mass only rises 5 degrees.
The 50 gram mass rises 10 degrees.
We know the perimeter formula would be 1200=2x+2y. And the area will be A=x*y
We can to take the derivative of the area formula to find where it is a max but we must first substitute something in from the first formula so we only have one variable.
1200-2x=2y
600-x=y
A=(x)*(600-x)
A=600x-x^2
Now we take the derivative:
A'=600-2x (set equal to 0 and solve)
0=600-2x
2x=600
x=300
Then when we plug this into the perimeter formula, we can solve for y
1200=2x+2y
1200=2(300)+2y
1200=600+2y
600=2y
y=300
So both the length and width are 300 yards, and the area would be 90,000 square yards
Hope this helps
Based on the given data set:
x 1 2 3 4 5
y 1 8 27 64 125
the relationship between the two variables is notably:
y = x^3
this formula represents the volume of a cube:
V = s^3
Therefore, the answer is C) Side length and volume of a cube.
Answer:
You would need more cubes because since the volume is decreased, you would need more cubes to fill up the original volume of 120 inches cubed. If the cubes were 2 inches, you would need 60. But if it was a half, you would need 240.
Step-by-step explanation:
Did that even help 0.0