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Pie
2 years ago
7

Please help i am confused

Mathematics
1 answer:
son4ous [18]2 years ago
7 0

Answer: (4)

Step-by-step explanation:

The parts listed in the congruence statements don't correspond, so they aren't necessarily congruent.

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Solve 2cos(x)-4sin(x)=3 [0,360]
Korvikt [17]
2cos(x) - 4sin(x) = 3

use identity  [cos(x)]^2 +[ sin(x)]^2 = 1 => cos(x) = √[1 - (sin(x))^2]

2√[1 - (sin(x))^2] - 4 sin(x) = 3

2√[1 - (sin(x))^2] = 3 + 4 sin(x)

square both sides

4[1 - (sin(x))^2] = 9 + 24 sin(x) + 16 (sin(x))^2

expand, reagrup and add like terms

4 - 4[sin(x)]^2 = 9 + 24sin(x) + 16sin^2(x)

20[sin(x)]^2 + 24sin(x) +5 = 0

use quadratic formula and you get sin(x) = -0.93166 and sin(x) = -0.26834

Now use the inverse functions to find x:

arcsin(-0.93166) = 76.33 degrees

arcsin(-0.26834) = 17.30 degrees






3 0
3 years ago
Someone please help me
Darya [45]
They both are complementary, so their sum would be 90 degrees.
5x-12 + 4x+3 =90
9x - 9 = 90
9x = 99
x = 11

So, angle 1 = 5x-12 = 5(11)-12 = 55-12 = 43
angle 2 = 4x+3 = 4(11)+3 = 44+3 = 47

So, your final answers are: angle 1 = 43 degrees & angle 2 = 47 degrees

Hope this helps!
7 0
3 years ago
129,543 rounded to the nearest ten thousand
Ksju [112]
130,000 129,543 is rounded up because the thousands place is a 9
5 0
2 years ago
Part III: Find the unknown side lengths, AB and BC. HINT: Use either the Pythagorean Theorem or special right triangle propertie
yaroslaw [1]

The measurement of sides AB, BC, and AC will be 3 units,3 units, and 3√2 units respectively.

<h3>What is a right-angle triangle?</h3>

If any of its inner angles is 90 degrees, the triangle is said to be right-angled. Another term for this triangle is the right triangle or 90-degree triangle.

From the given triangle, it is observed that one of the angles is 90°, showing the given triangle is a right-angle triangle.

From the Δ ABC we found;

tan 45° = AB/BC

1=AB/BC

AB=BC

sin 45° = AB/AC

(1/√2)=AB/AC

AC = √2 AB

From the graph, it is observed that

AB=BC =3 units

AC=  √2 AB

AC = 3√2 units

Hence, the measurement of sides AB, BC, and AC will be 3 units,3 units, and 3√2 units respectively.

To learn more about the right-angle triangle, refer;

brainly.com/question/3770177

#SPJ1

4 0
1 year ago
Complete the table of values
Agata [3.3K]
Both problems give you a function in the second column and the x-values. To find out the values of a through f, you need to plug in those x-values into the function and simplify! 

You need to know three exponent rules to simplify these expressions:
1) The negative exponent rule says that when a base has a negative exponent, flip the base onto the other side of the fraction to make it into a positive exponent. For example, 3^{-2} =&#10;\frac{1}{3^{2} }.
2) Raising a fraction to a power is the same as separately raising the numerator and denominator to that power. For example, (\frac{3}{4}) ^{3}  =  \frac{ 3^{3} }{4^{3} }.
3) The zero exponent rule<span> says that any number raised to zero is 1. For example, 3^{0} = 1.
</span>

Back to the Problem:
Problem 1 
The x-values are in the left column. The title of the right column tells you that the function is y =  4^{-x}. The x-values are:
<span>1) x = 0
</span>Plug this into y = 4^{-x} to find letter a:
y = 4^{-x}\\&#10;y = 4^{-0}\\&#10;y = 4^{0}\\&#10;y = 1
<span>
2) x = 2
</span>Plug this into y = 4^{-x} to find letter b:
y = 4^{-x}\\ &#10;y = 4^{-2}\\ &#10;y =  \frac{1}{4^{2}} \\  &#10;y= \frac{1}{16}
<span>
3) x = 4
</span>Plug this into y = 4^{-x} to find letter c:
y = 4^{-x}\\ &#10;y = 4^{-4}\\ &#10;y =  \frac{1}{4^{4}} \\  &#10;y= \frac{1}{256}
<span>

Problem 2
</span>The x-values are in the left column. The title of the right column tells you that the function is y =  (\frac{2}{3})^x. The x-values are:
<span>1) x = 0
</span>Plug this into y = (\frac{2}{3})^x to find letter d:
y = (\frac{2}{3})^x\\&#10;y = (\frac{2}{3})^0\\&#10;y = 1
<span>
2) x = 2
</span>Plug this into y = (\frac{2}{3})^x to find letter e:
y = (\frac{2}{3})^x\\ y = (\frac{2}{3})^2\\ y = \frac{2^2}{3^2}\\&#10;y =  \frac{4}{9}
<span>
3) x = 4
</span>Plug this into y = (\frac{2}{3})^x to find letter f:
y = (\frac{2}{3})^x\\ y = (\frac{2}{3})^4\\ y = \frac{2^4}{3^4}\\ y = \frac{16}{81}
<span>
-------

Answers: 
a = 1
b = </span>\frac{1}{16}<span>
c = </span>\frac{1}{256}
d = 1
e = \frac{4}{9}
f = \frac{16}{81}
5 0
3 years ago
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