Question

What is (-m)^-3n if m=2 and n=-24?

Answer 1

N(-m)⁻³

remember order of operations and
$x^{-m}= \frac{1}{x^m}$ so
simplify the exponent first

$(-m)^{-3}= \frac{1}{(-m)^3}= \frac{1}{-m^3}$
now multiply by n
$\frac{n}{-m^3}$

n=-24
m=2


$\frac{-24}{-2^3}$
$\frac{-24}{-8}$
3

the result is 3