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lisabon 2012 [21]
3 years ago
6

What is (-m)^-3n if m=2 and n=-24?

Mathematics
1 answer:
kap26 [50]3 years ago
3 0
N(-m)⁻³

remember order of operations and
x^{-m}= \frac{1}{x^m} so
simplify the exponent first

(-m)^{-3}= \frac{1}{(-m)^3}= \frac{1}{-m^3}
now multiply by n
\frac{n}{-m^3}

n=-24
m=2


\frac{-24}{-2^3}
\frac{-24}{-8}
3

the result is 3
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