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tatyana61 [14]
3 years ago
5

Five out of six residents of Mayville have library cards. Which tool will best allow Darren to simulate this scenario and predic

t whether a randomly chosen resident has a library card?
Mathematics
1 answer:
Readme [11.4K]3 years ago
8 0

Answer:

A number cube

Step-by-step explanation:

A coin a 5-sector spinner a number cube a bag of 11 marbles

A number cube is the best to simulate this scenario and predict whether a randomly chosen resident has a library card.

As Coin has only 2 outcomes "Head" and "Tail".

A 5-sector sector spinner has only 5 outcomes we need six outcomes.

A bag of 11 marbles has no differentiated with respect to colors etc.

Hence, A number cube is correct to chosen five out of six residents of Mayville have library cards.

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Yes im playing prodigy LOL
Ilya [14]

Answer:

0,05

Step-by-step explanation:

1)First, Let’s find the mean of the data table

12 + 10 + 12 + 6 + 8 + 4 + 2 + 12 = 66

66 ÷ 8 = 8,25

2)12 - 8,25 = 3,75

10 - 8,25 = 1,25

12 - 8,25 = 3,75

6 - 8,25 = -1,75

8 - 8,25 = -0,75

4 - 8,25 = -3,75

2 - 8,25 = -5,75

12 - 8,25 = 3,75

3) 3,75 + 1,25 + 3,75 - 1,75 - 0,85 - 3,75 - 5,75 + 3,75 = 0,4

0,4 ÷ 8 = 0,05

8 0
3 years ago
A and B are two events.
Vesna [10]
In order to determine if the events are independent or not we need to find the conditional probabilities.

The conditional probability of event A, given event B is denoted as P(A|B)

P(A|B)= \frac{P(A*B)}{P(B)}

P(A*B) indicates P(A and B)

Using the values, we get:

P(A|B)= \frac{0.28}{0.8}=0.35

Since P(A|B) is not equal to P(A) this indicates that occurrence of event B has an impact on the occurrence of event A. This shows that the two events are dependent.

Therefore, the correct option is the second one.
2. A and B are not independent events because P(A∣∣B)≠P(A)
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