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tresset_1 [31]
2 years ago
15

At the start of the month, Suzanne's clothing store website had 7,278 hits. At the end of the month, it had 50,165 hits. If each

hit lasted 1.5 minutes, then what was the approximate total number of minutes on the website for this month? A. 64,500 B. 43,651 C. 21,955 D. 102,200
Mathematics
1 answer:
anyanavicka [17]2 years ago
3 0

Answer:

  • <u><em>Option A. 64,500</em></u>

Explanation:

1. First, calculate the number of hits had during the month, by difference:

  • 50,165 hits - 7,278 hits = 42,887 hits

2. Round the result to obtain an approximation = 43,000 hits

3. Multiply by the time that each lasted:

  • 43,000 hits × 1.5 min/hit = 64,500 minutes.

Hence, the answer is the option A.

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Need help on 15 and 16 PLEASEE!!!
melisa1 [442]

Answer:

Part 15) The next three terms are 5/8,3/4 and 7/8

Part 16) The 37th term is -35.5

Step-by-step explanation:

we know that

In an <u>Arithmetic Sequence</u> the difference between one term and the next is a constant and this constant is called the common difference (d)

Part 15) Find the next three terms of the arithmetic sequence

\frac{1}{8},\frac{1}{4},\frac{3}{8},\frac{1}{2},...

so

a1=1/8\\ a2=1/4\\ a3=3/8\\ a4=1/2\\ a2-a1=1/4-1/8=1/8\\ a3-a2=3/8-1/4=1/8\\ a4=a3=1/2-3/8=1/8

The common difference is equal to

d=1/8

<u><em>Find the next three terms of the arithmetic sequence</em></u>

<u><em>Find a5</em></u>

a5=a4+d ----->a5=1/2+1/8=5/8

<u><em>Find a6</em></u>

a6=a5+d ----->a6=5/8+1/8=3/4

<u><em>Find a7</em></u>

a7=a6+d ----->a7=3/4+1/8=7/8

therefore

The next three terms are

5/8,3/4 and 7/8

Part 16) what is the 37th term of the arithmetic sequence

4.1,3,1.9,0.8,...?

so

a1=4.1\\ a2=3\\ a3=1.9\\ a4=0.8

a2-a1=3-4.1=-1.1\\ a3-a2=1.9-3=-1.1\\ a4=a3=0.8-1.9=-1.1

The common difference is equal to

d=-1.1

We can write an Arithmetic Sequence as a rule

an=a1+d(n-1)

substitute the values

an=4.1-1.1(n-1)

For n=37

substitute

a37=4.1-1.1(37-1)

a37=4.1-1.1(36)

a37=-35.5

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