<span>B)
8 ft
6, 8, 10 are lengths of a Pythagorean triple
6^2 + 8^2 = 10^2</span><span>
</span>
Answer:
Step-by-step explanation:
y ≤ 5x - 1
- 5x + y ≤ - 1
5x - y ≥ 1
Answer:
x>14
hope this helped
Answer:
I thinks it's y=3x+5
Step-by-step explanation:
try to use desmos to calculate it
Length (2, 6) to (-4, 6) is sqrt((x2 - x1))^2 + (y2 - y1)^2) = sqrt((-4 -2)^2 + (6 - 6)^2) = sqrt((-6)^2 + 0) = 6
Length (2, 6) to (-4, 4) is sqrt((-4 - 2)^2 + (4 - 6)^2) = sqrt((-6)^2 + (-2)^2) = sqrt(36 + 4) = sqrt(40) = 2sqrt(10) units
Length (-4, 6) to (-4, 4) is sqrt((-4 - (-4))^2 + (4 - 6)^2) = sqrt(0^2 + (-2)^2) = 2
Therefore, the length of the longest side is 2sqrt(10) units
