The height of the object after 1 sec is 284 feet
<h3>Equation of height of an object</h3>
Given the equation of height of an object expressed as:
h(t) = -16t^2 + 300t
We are to find the height of the object after 1 sec. To do that, we will substitute t = 1 into the following expression
h(t) = -16t^2 + 300t
h(1) = -16(1)^2 + 300(1)
h(1) = -16 + 300
h(1) = 284ft
Hence the height of the object after 1 sec is 284 feet
Learn more on maximum height here: brainly.com/question/12446886
Answer is x=53
hope this helps
Using derivatives, it is found that the correct option is:
A. Object C has an acceleration that is greater than the acceleration for D.
The acceleration is the <u>derivative of the velocity</u>, given by change in velocity divided by change in time, that is:

In this problem:
- The change in time for objects C and T is the same.
- The <u>change in velocity for object C is greater</u>, thus, it has a greater acceleration, and the correct option is:
A. Object C has an acceleration that is greater than the acceleration for D.
A similar problem is given at brainly.com/question/14516604
3/10 that's what the answer is