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brilliants [131]
3 years ago
8

From the numbers 1 through 10 which one of these statements is true

Mathematics
2 answers:
Rudik [331]3 years ago
8 0
Numbers over five-6,7,8,9,10 (5 numbers). Numbers under five-1,2,3,4 (only 4 numbers). Therefore its B..
eimsori [14]3 years ago
6 0

The correct answer is B
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Which of the following equations has no solution?
daser333 [38]

Answer:

B. 3x+5−4x=−(x+8)

Explanation:

3x+5−4x=−(x+8)

Step 1: Simplify both sides of the equation.

3x+5−4x=−(x+8)

3x+5+−4x=−x+−8

(3x+−4x)+(5)=−x−8

−x+5=−x−8

−x+5=−x−8

Step 2: Add x to both sides.

−x+5+x=−x−8+x

5=−8

Step 3: Subtract 5 from both sides.

5−5=−8−5

0=−13

So, there is no solution

Hope this Helps!

8 0
3 years ago
Read 2 more answers
Write a definite integral that represents the area of the region. (Do not evaluate the integral.) y1 = x2 + 2x + 3 y2 = 2x + 12F
Svet_ta [14]

Answer:

A = \int\limits^3__-3}{9}-{x^{2}} \, dx = 36

Step-by-step explanation:

The equations are:

y = x^{2} + 2x + 3

y = 2x + 12

The two graphs intersect when:

x^{2} + 2x + 3 = 2x + 12

x^{2} = 0

x_{1}  = 3\\x_{2}  = -3

To find the area under the curve for the first equation:

A_{1} = \int\limits^3__-3}{x^{2} + 2x + 3} \, dx

To find the area under the curve for the second equation:

A_{2} = \int\limits^3__-3}{2x + 12} \, dx

To find the total area:

A = A_{2} -A_{1} = \int\limits^3__-3}{2x + 12} \, dx -\int\limits^3__-3}{x^{2} + 2x + 3} \, dx

Simplifying the equation:

A = \int\limits^3__-3}{2x + 12}-({x^{2} + 2x + 3}) \, dx = \int\limits^3__-3}{9}-{x^{2}} \, dx

Note: The reason the area is equal to the area two minus area one is that the line, area 2, is above the region of interest (see image).  

3 0
3 years ago
4. Andrés desea embaldosar el piso de su casa que tiene 375 cm de ancho y 435 cm de largo. Calcula la longitud del lado que tend
svetlana [45]

Answer:

Sabemos que el piso es un rectángulo de 435 cm de largo y 375 cm de ancho.

Recordar que para un rectángulo de largo L, y ancho W, el área es:

A = L*W

Entonces el área del piso, será:

A = 435cm*375cm = 163,125 cm^2

Primero, sabemos que se utilizaran baldosas (las cuales son cuadradas) y queremos saber la longitud de lado que tendrían las baldosas.

No tenemos ningún criterio para encontrar este lado, solo que (si queremos usar un número entero de baldosas) el largo L del lado de la baldosa deberá ser un divisor de tanto el ancho como el largo del suelo.

Dicho de otra forma

el largo, 435cm, tiene que ser múltiplo de L

el ancho, 375cm, tiene que ser múltiplo de L.

Por ejemplo, ambos números son múltiplos de 5, entonces podríamos tomar L = 5cm

En este caso, el área de cada baldosa es:

a = L^2 = 5cm*5cm = 25cm^2

Y el número total de baldosas que necesitaría usar esta dado por el cociente entre el área del suelo y el area de cada baldosa.

N = ( 163,125 cm^2)/(25cm^2) = 6,525 baldosas.

También sabemos que ambos números (435cm y 375cm) son múltiplos de 15cm

Entonces las baldosas podrían tener 15cm de lado.

En este caso, el área de cada baldosa es:

A = (15cm)^2 = 225cm

En este caso el número total de baldosas necesarias será:

N =  ( 163,125 cm^2)/(225cm^2) = 725 baldosas.

5 0
3 years ago
Which one represents a function?
MArishka [77]

Answer:

Step-by-step explanation:

Figure it out

6 0
3 years ago
Select all of the following that are quadratic equations. 7x2 + 14x = 0 x3 - 3x2 + 1 = 0 5x - 7 = 0 x2 + 3x -5 = 0 x - 5 = 9x +
Tpy6a [65]

Answer:

7x2 + 14x = 0

x2 + 3x -5 = 0

x2 - x = 3x + 7  

Step-by-step explanation:

A quadratic equation has the highest power of x to the second power.  It must have x to the second power

7x2 + 14x = 0  quadratic

x3 - 3x2 + 1 = 0   not quadratic  but cubic

5x - 7 = 0  not quadratic  but linear

x2 + 3x -5 = 0   quadratic

x - 5 = 9x + 7  not quadratic but linear

x2 - x = 3x + 7  quadratic

4 0
2 years ago
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