Answer:
x = 3.748
Step-by-step explanation:
this problem requires logs
x = 2 + log_7 (30) or 3.7479
The answer would be C. to find this use the rise over run method
Answer:
Bus speed: 22 mph; Trolley speed: 14 mph
Step-by-step explanation:
Let rb represent the speed of the bus and rt the speed of the trolley. Then rb = rt + 8 (mph).
Recall that distance = rate times time. Two different distances and two different speeds are involved here, but only one time.
Thus,
60 mi 44 mi
--------------------- = time (same in both cases) = -------------
rt + 8 mi/hr rt
Cross-multiplying, we get 44rt + 8(44) = 60 rt, or
352 = 16rt.
Solving this for rt, we get rt = speed of bus = 352/16 = 22 mph
The speed at which the bus travels is 22 mph and that at which the trolley travels is (22 mph - 8 mph) = 14 mph
Answer:
It is odd
Step-by-step explanation:
For example let's substitute 1 for x
f(x) = 4(1)+3
4+3
f(x) = 7 this is odd
Let's substitute 2
f(x) = 4(2)+3
8+3
f(x) = 11 this is odd
This means no matter what you substitute for x, it will be odd
Hope this helps!
