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sveticcg [70]
3 years ago
8

What is J=4rb solved for r?

Mathematics
2 answers:
AURORKA [14]3 years ago
5 0
Your answer is A (R=j/4b)
kolbaska11 [484]3 years ago
3 0
J=4rb  divide both sides by 4b

r=j/(4b)
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Solve the compound inequality <br><br> 4 (x-5) &lt;12 or x+2&gt;9
arsen [322]
Answer would be -19 and your welcome :) 
8 0
3 years ago
Please help!! WILL MARK BRAINLIEST
d1i1m1o1n [39]

Answer:

a=  2/5

b= 30

c= 18

d=   3:2

e=  No, because the fraction or ratio is the same, all you need to do is simplify it!

5 0
3 years ago
Emma was about to finish grocery shopping when she noticed that cans of soup were on sale. Her total bill for groceries would be
Alinara [238K]

Answer:

3rd option: B(C)= 1.79C +86.03

Step-by-step explanation:

Total bill

= cost of cans(number of cans) +cost of other groceries

Let the cost of other groceries be G, and the cost of cans be X.

Given that number of cans= C,

Total bill= XC +G

If 2 cans were purchased,

2X+G= 89.61 -----(1)

If 5 cans were purchased,

5X +G= 94.98 -----(2)

(2) -(1):

(5X +G) -(2X +G)= 94.98 -89.61

5X +G -2x -G= 5.37

3X= 5.37

X= 5.37 ÷3 <em>(</em><em>÷</em><em>3</em><em> </em><em>on</em><em> </em><em>both</em><em> </em><em>sides</em><em>)</em>

X= 1.79

Subst. X= 1.79 into (1):

2(1.79) +G= 89.61

3.58 +G= 89.61

G= 89.61 -3.58 <em>(</em><em>-3.58</em><em> </em><em>on</em><em> </em><em>both</em><em> </em><em>sides</em><em>)</em>

G= 86.03 <em>(</em><em>simplify</em><em>)</em>

Total bill

= XC +G

= 1.79C +86.03

Thus, the function is B(C)= 1.79C +86.03.

3 0
3 years ago
7. Find the perimeter of triangle FGH.
belka [17]

Answer:

9.) Its equilateral

7.) 24

Step-by-step explanation:

Sorry I only have the answer for 7 and 9.

3 0
3 years ago
Evaluate the expression if m = 3.<br><br> 3m^2<br><br><br> (SHOW YOUR WORK)
iragen [17]

The value of given expression when m = 3 is 27

<h3><u>Solution:</u></h3>

Given expression is 3m^2

We have to evaluate the given expression for m = 3

To find for m is equal to 3, substitute m = 3 in given expression

From given expression,

\rightarrow 3m^2

Plug in m = 3 in above expression

\rightarrow 3(3)^2 ------ eqn 1

We know that,

a^2 can be expanded as,

a^2=a \times a

Applying this in eqn 1, we get

\rightarrow 3(3)^2=3 \times (3 \times 3)

Simplify the above expression

\rightarrow 3(3)^2=3 \times (3 \times 3) = 3 \times 9 = 27

Therefore, for m = 3 we get,

\rightarrow 3(3)^2=27

Thus value of given expression when m = 3 is found

5 0
3 years ago
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