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3 years ago

7

Addison budgets $120 for circus training. She buys a book about the art of juggling for $12 and pays $25 per circus class. Write

an inequality that represents the number of classes, c, that Addison can take and stay within her budget?

1 answer:

olya-2409 [2.1K]3 years ago

6 0

Answer:

Step-by-step explanation:

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Ave: 7k- 14 = 42<br> How do you solve it

Misha Larkins [42]

Answer:

Im going to guess k is the unknown

Step-by-step explanation:

7k-14=42

42+14=7k

56=7k

56/7=k

k=8

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N-m-m; use m=6,and n=-5

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Answer:

1.) The product of 12 and 3/4 is less than 12. This is because you are multiplying 12 by a number less than 1.

2.) The product of 5 and 1/2 is less than 5, this is because you are multiplying 5 by a number less than one.

Step-by-step explanation:

If multiplied by a number less than one then it will be smaller than original

If multiplied by one will be the same as original

If multiplied by a number greater than one it will be greater than original

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3 years ago

Write an equation of a parabola that passes through (3,-30) and has x-intercepts of -2 and 18. Then find the average rate of cha

Nookie1986 [14]

Answer:

The equation of the parabola is $y = \frac{2}{5}\cdot x^{2}-\frac{32}{5}\cdot x -\frac{72}{5}$ . The average rate of change of the parabola is -4.

Step-by-step explanation:

We must remember that a parabola is represented by a quadratic function, which can be formed by knowing three different points. A quadratic function is standard form is represented by:

$y = a\cdot x^{2}+b\cdot x + c$

Where:

$x$ - Independent variable, dimensionless.

$y$ - Dependent variable, dimensionless.

$a$ , $b$ , $c$ - Coefficients, dimensionless.

If we know that $(3, -30)$ , $(-2, 0)$ and $(18, 0)$ are part of the parabola, the following linear system of equations is formed:

$9\cdot a +3\cdot b + c = -30$

$4\cdot a -2\cdot b +c = 0$

$324\cdot a +18\cdot b + c = 0$

This system can be solved both by algebraic means (substitution, elimination, equalization, determinant) and by numerical methods. The solution of the linear system is:

$a = \frac{2}{5}$ , $b = -\frac{32}{5}$ , $c = -\frac{72}{5}$ .

The equation of the parabola is $y = \frac{2}{5}\cdot x^{2}-\frac{32}{5}\cdot x -\frac{72}{5}$ .

Now, we calculate the average rate of change ( $r$ ), dimensionless, between $x = -2$ and $x = 8$ by using the formula of secant line slope:

$r = \frac{y(8)-y(-2)}{8-(-2)}$

$r = \frac{y(8)-y(-2)}{10}$

$x = -2$

$y = \frac{2}{5}\cdot (-2)^{2}-\frac{32}{5}\cdot (-2)-\frac{72}{5}$

$y(-2) = 0$

$x = 8$

$y = \frac{2}{5}\cdot (8)^{2}-\frac{32}{5}\cdot (8)-\frac{72}{5}$

$y(8) = -40$

$r = \frac{-40-0}{10}$

$r = -4$

The average rate of change of the parabola is -4.

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Use the following federal tax table for biweekly gross earnings of a single person to help answer the question below.

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a. Is the answer hope you passed!!!

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