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Feliz [49]
3 years ago
7

Addison budgets $120 for circus training. She buys a book about the art of juggling for $12 and pays $25 per circus class. Write

an inequality that represents the number of classes, c, that Addison can take and stay within her budget?
Mathematics
1 answer:
olya-2409 [2.1K]3 years ago
6 0

Answer:

Step-by-step explanation:

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Math Algebra 1 Honors Unit 4 that's what it is ​
dezoksy [38]

Answer:

Unit 4- Expressions and Equations: In this unit, students build on their knowledge from unit 2, where they extended the laws of exponents to rational exponents. Students apply this new understanding of number and strengthen their ability to see structure in and create quadratic and exponential expressions.

4 0
2 years ago
Help Please, Look at attachments
Anastasy [175]

Answer:

y=-4x+4

Step-by-step explanation:

The slope is Delta Y over Delta Y so the slope is -4. The Y intercept is at (0,4) sot the equations is y= - 4x +4

4 0
2 years ago
Read 2 more answers
What is the value of (7 + 2i)(3 - i)?
Harrizon [31]
There are two ways to work this out: normal variables or using "imaginary" numbers.

Normal variables:
(7+2i)(3-i)\\(7*3)+[7*(-i)]+(3*2i)+[2i*(-i)]\\21-7i+6i-2i^{2}\\\\21-i-2i^{2}

Imaginary numbers:
Using the result from earlier:
21-i-2i^{2}
Now since i = \sqrt{-1}, then the expression becomes:
21-i-2i^{2}\\21-i-2(\sqrt{-1})^{2}\\21-i+(-2)(-1)\\21-i+2\\\\23-i
7 0
3 years ago
Solve for x. one fifth times the absolute value of the quantity x minus 4 end quantity minus 3 equals 6 A. x= -19 and x =-11 b.
Firdavs [7]

The value of x in the given expression can be either -41 or 45. The correct option is B.

<h3>What is Absolute Value?</h3>

An absolute value of |x| {modulus of x} is the value of a real number x, the value we get is always a non-negative number, for example, |-5| will give 5, and also, |5| will give 5 as well.

Given the modulus function (1/5)|x - 4| - 3 = 6. Now, there will be two cases of this because the value of x can be either negative, x<0 or it can positive, x>0. Therefore, the given modulus function can be solved as shown below.

  • When x>0,

(1/5)(x-4) - 3 = 6

(x/5) - (4/5) - 3 = 6

(x - 4 - 15)/5 = 6

x - 4 -15 = 30

x = 30 + 15 + 4

x = 45

  • When x<0

(1/5)(-x+4) - 3 = 6

(-x/5) + (4/5) - 3 = 6

(- x + 4 - 15)/5 = 6

- x + 4 -15 = 30

-x = 30 + 15 - 4

-x = 41

x = -41

Hence, the value of x in the given expression can be either -41 or 45.

Learn more about Absolute value here:

brainly.com/question/1301718

#SPJ1

6 0
1 year ago
Simplify the given equation in the attached picture:<br><br>\sqrt{29-\sqrt{5}}
Vilka [71]

Answer: 2√5 - 3

Step-by-step explanation:

$$Simplify the following:$\sqrt{29-12 \sqrt{5}}$$$\begin{aligned}&29-12 \sqrt{5}=9-12 \sqrt{5}+20=9-12 \sqrt{5}+4(\sqrt{5})^{2}=(2 \sqrt{5}-3)^{2}: \\&\sqrt{\left((2 \sqrt{5}-3)^{2}\right)}\end{aligned}$$Cancel exponents. $\sqrt{(2 \sqrt{5}-3)^{2}}=2 \sqrt{5}-3$ :\\Answer:$$2 \sqrt{5}-3$$

3 0
2 years ago
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