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Feliz [49]
3 years ago
7

Addison budgets $120 for circus training. She buys a book about the art of juggling for $12 and pays $25 per circus class. Write

an inequality that represents the number of classes, c, that Addison can take and stay within her budget?
Mathematics
1 answer:
olya-2409 [2.1K]3 years ago
6 0

Answer:

Step-by-step explanation:

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When I sit and watch my students take exams, I often think to myself "I wonder if students with bright calculators are impacted
hodyreva [135]

Answer:

There is a difference between the two means.

Step-by-step explanation:

The hypothesis can be defined as:

<em>H₀</em>: The mean exam scores of my SAT 215 students with colorful calculators are same as the mean scores of my STA 215 students with plain black calculators, i.e. <em>μ</em>₁ - <em>μ</em>₂ = 0.

<em>Hₐ</em>: The mean exam scores of my SAT 215 students with colorful calculators are different than the mean scores of my STA 215 students with plain black calculators, i.e. <em>μ</em>₁ - <em>μ</em>₂ ≠ 0.

Assume that the significance level of the test is, <em>α</em> = 0.05. Also assuming that the population variances are equal.

The decision rule:

A 95% confidence interval for mean difference can be used to determine the result of the hypothesis test. If the 95% confidence interval contains the null hypothesis value, i.e. 0 then the null hypothesis will not be rejected.

The 95% confidence interval for mean difference is:

CI=\bar x_{1}-\bar x_{2}\pm t_{\alpha/2, (n_{1}+n_{2}-2)}\times S_{p}\times \sqrt{\frac{1}{n_{1}}+\frac{1}{n_{2}}}

Compute the pooled standard deviation as follows:

S_{p}=\sqrt{\frac{(n_{1}-1)s_{1}^{2}+(n_{2}-1)s_{2}^{2}} {n_{1}+n_{2}-2}}}=\sqrt{\frac{(49-1)(4.7)^{2}+(38-1)(5.7)^{2}}{49+38-2}}=5.16

The critical value of <em>t</em> is:

t_{\alpha/2, (n_{1}+n_{2}-2)}=t_{0.05/2, (49+38-2)}=t_{0.025, 85}=1.984

*Use a <em>t</em>-table.

Compute the 95% confidence interval for mean difference as follows:

CI=\bar x_{1}-\bar x_{2}\pm t_{\alpha/2, (n_{1}+n_{2}-2)}\times S_{p}\times \sqrt{\frac{1}{n_{1}}+\frac{1}{n_{2}}}

     =(84-87)\pm 1.984\times 5.16\times \sqrt{\frac{1}{49}+\frac{1}{38}}

     =-3\pm 2.133\\=(-5.133, -0.867)\\\approx(-5.13, -0.87)

The 95% confidence interval for mean difference is (-5.13, -0.87).

The confidence interval does not contains the value 0. This implies that the null hypothesis will be rejected at 5% level of significance.

Hence, concluding that the mean exam scores of my STA 215 students with colorful calculators are different than the mean scores of my STA 215 students with plain black calculators.

7 0
3 years ago
A 3x33 cube is built out of twenty-seven 1x1x1 blocks. Then,
EastWind [94]

Answer:-7^2(negitive seven to the second power)

Step-by-step explanation:

7 0
3 years ago
Five years ago, Nina was twice as old as Sam. In five years, she will be 1.5 times as old as Sam. How old are Nina and Sam now?
Margarita [4]

Answer:

age of Sam= 15 years

age of Nina  = 25 years

Step-by-step explanation:

Let  Nina's age be X years

Let  Sam's age be Y years

Five years ago Nina's age will be X- 5 years

Five years ago Sam's age will be Y- 5 years

Given in question

Five years ago, Nina was twice as old as Sam

writing it mathematically using X and Y we have

Nina's age = 2 * Sam's age

X- 5 = 2 *(Y- 5)

X = 2 *(Y- 5) + 5 = 2Y - 10 + 5 = 2Y - 5  _________________equation A

__________________________________________________________

Five years in future Nina's age will be X+ 5 years

Five years ago Sam's age will be Y+ 5 years

Given in question

In five years, she will be 1.5 times as old as Sam

writing it mathematically using X and Y we have

Nina's age = 1.5 * Sam's age

X+5 = 1.5 *(Y+ 5)

X = 1.5*(Y+5) -5 = 1.5Y +7.5 - 5 = 1.5Y +2.5  _________________equation B

_______________________________________

in equation A we have X = 2Y - 5

in equation B we have X = 1.5Y + 2.5

equating equation A and B  we have

2Y - 5 = 1.5Y +2.5

=> 2Y - 1.5Y = 2.5 + 5

=> 0.5Y = 7.5

=> Y = 7.5/0.5 = 15

from equation A we have

X = 2Y - 5  (substituting the value of Y = 15 in equation we have)

X = 2*15 - 5 = 25

Therefore age of Sam= 15 years

age of Nina  = 25 years

4 0
3 years ago
Area of a 90in 3yd rectangle
Free_Kalibri [48]
Hello,

Converting 90 in to yd, we have:
90in * 1ft/12in * 1yd/3ft = 2.5 yd

Next,
Since A of a rectangle is b*h,
A = 2.5yd * 3yd = 7.5 yd ^2.

Good luck to you!
5 0
3 years ago
Divide.<br> 1.6 23.2 <br> I need help I’m gonna cry.
aivan3 [116]

Answer:

use a calculator

Step-by-step explanation:

its not that hard

3 0
3 years ago
Read 2 more answers
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