money going out (20.38+11.48+19.50) =51.36
balance - out = new balance
65.40-51.36 =
14.04
new balance = 14.04
Answer:
3+x sqrt 7 -13 is a radical equation.
The given is that A B C D <span>x 4 = D C B A
</span><span>
Possible values of A are 1 or 2. It can't be 1 since the </span><span> </span><span>final result A is in unit place and 1 is not possible when we multiply any number by 4
</span><span>
2 B C D x </span><span>4 = </span><span>D C B 2</span>
It is clear above, that D = 8
2 B C 8 x <span>4 = </span><span>8 C B 2</span>
Possible values of B should be 1 or 2
We try B=1
2 1 C 8 x <span>4 = </span><span>8 C 1 2
</span>To find for C, you can use the equation:
(2000+100+10C+8) x 4 = 8000+100C+10+240C = 432-12 = 420
Therefore,
C = 7
So, the number is 2178.
Answer:
4
Step-by-step explanation:
The y-variable can be eliminated by adding 3 times the first equation to the second:
3(2x -y) +(x +3y) = 3(11) +(-5)
7x = 28 . . . . simplify
x = 4 . . . . . . . divide by 7
_____
Using Cramer's Rule, you can also find the x-value. The math is not so different.
x = ((-1)(-5) -(3)(11))/(-1(1) -3(2)) = -28/-7 = 4
<u>Answer-</u>
<em>The probability that a randomly selected recipe does not contain sugar, given that it contains salt is 22.4%</em>
<u>Solution-</u>
The given table in the link shows the relative frequencies of recipes that contains sugar and salt, or contains at least one of those ingredients, or contains neither of those ingredients.
We have to find the conditional probability that the recipe doesn't contain sugar, given that it contains salt.
We know that, the conditional probability of occurrence of A given that B occurs is,



Putting these values,
