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anygoal [31]
3 years ago
13

Which expression is equivalent to 1/4-3/4x? 1/4(1+3x) 1/4(1-3x) 1/4(-1+3x) 4(1+3x)

Mathematics
1 answer:
o-na [289]3 years ago
5 0

Answer:1/4(1-3x)

Step-by-step explanation:

You might be interested in
A sector of a circle makes a 127° angle at its centre. If the arc of the sector has length 36 mm, find
Veseljchak [2.6K]

Answer:

Approximately 68.5\; \rm mm.

Step-by-step explanation:

Convert the angle of this sector to radians:

\begin{aligned}\theta &= 127^{\circ} \\ &= 127^{\circ} \times \frac{2\pi}{360^{\circ}} \\ &\approx 2.22\end{aligned}.

The formula s = r\, \theta relates the arc length s of a sector of angle \theta (in radians) to the radius r of this sector.

In this question, it is given that the arc length of this sector is s = 36\; \rm mm. It was found that \theta = 2.22 radians. Rearrange the equation s = r\, \theta to find the radius r of this sector:

\begin{aligned} r&= \frac{s}{\theta} \\ &\approx \frac{36\; \rm mm}{2.22} \\ &\approx 16.2\; \rm mm\end{aligned}.

The perimeter of this sector would be:

\begin{aligned}& 2\, r + s \\ =\; & 2 \times 16.2\; {\rm mm} + 36\; {\rm mm} \\ =\; & 68.5\; \rm mm\end{aligned}.

8 0
2 years ago
1. Two object accumulated a charge of
In-s [12.5K]

Answer:

The  magnitude of the electric force  between these two objects

will be: 181.274 N.

i.e.  F  =181.274 N

Step-by-step explanation:

As

Two object accumulated a charge of  4.5 μC and another a charge of 2.8  μC.

so

q₁ = 4.5 μC = 4.5 × 10⁻⁶ C

q₂ = 2.8  μC = 2.8 × 10⁻⁶  C

separated distance = d = 2.5 cm

Calculating the magnitude of the force between two charged objects using the formula:

F = \frac{1}{4\pi \epsilon_0}\frac{q_1 q_2}{r^2}

   =\:\frac{4.5\times \:\:10^{-6}\:\times \:\:2.8\:\times \:\:10^{-6}}{4\:\times \:\left(3.14\right)\:\times \:\left(8.85\times \:10^{-12}\right)\times \left(2.5\times \:\:10^{-2}\right)^2}

   =\frac{10^{-12}\times \:12.6}{10^{-12}\times \:4\times \:8.85\pi \left(10^{-2}\times \:2.5\right)^2}        ∵ 4.5\times \:10^{-6}\times \:2.8\times \:10^{-6}=10^{-12}\times \:12.6

   =\frac{10^{-12}\times \:12.6}{10^{-12}\times \:35.4\pi \left(10^{-2}\times \:2.5\right)^2}    ∵ \mathrm{Multiply\:the\:numbers:}\:4\times \:8.85=35.4

\mathrm{Cancel\:the\:common\:factor:}\:10^{-12}

  =\frac{12.6}{35.4\pi \left(10^{-2}\times \:2.5\right)^2}

  =\frac{12.6}{0.025^2\times \:35.4\pi }        ∵ \left(10^{-2}\times \:2.5\right)^2=0.025^2

  =\frac{12.6}{0.022125\pi }        ∵ 35.4\pi\times 0.025^2=0.022125\pi

   =\frac{12.6}{0.06950 }

F  =181.274 N

Therefore, the  magnitude of the electric force  between these two objects will be: 181.274 N.

i.e.  F  =181.274 N

7 0
3 years ago
The fair spinner shown in the diagram above is spun.
julsineya [31]

Answer:

1/5

Explanation:

There are five choices in the spinner. <em>One </em>of the choices is labeled '5'. That means you will have one out of the 5 choices to get the choice labeled '5'.

Good day :)

8 0
2 years ago
5m + 2[m+8] + 3 pls give answer<br> m = 2
abruzzese [7]
So m=2, wherever m is put a 2

5x2+2(2+8)+3

Then do bidmas

Brackets-

5x2+2x10+3

Multiplication-

10+20+3

Addition-

33

Answer:33
7 0
3 years ago
If SDE ~ SWT, find WT.
faust18 [17]

Formula used: 40+x = 4x-3 x is used for <em>ET</em>

Step-by-step explanation:

40+x = 4x-3

<u>+</u><u>3</u> <u>+</u><u>3</u>

43+x = 4x

<u>-</u><u>x</u> <u>-</u><u>x</u>

<u>43</u> = <u>3x</u>

3 3

14.3 = x

then substitude this on 5x+3 on <em>W</em><em>T</em> and you arr good

5 0
3 years ago
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