Which expression is equivalent to 1/4-3/4x? 1/4(1+3x) 1/4(1-3x) 1/4(-1+3x) 4(1+3x)

A sector of a circle makes a 127° angle at its centre. If the arc of the sector has length 36 mm, find

Veseljchak [2.6K]

Answer:

Approximately $68.5\; \rm mm$ .

Step-by-step explanation:

Convert the angle of this sector to radians:

$\begin{aligned}\theta &= 127^{\circ} \\ &= 127^{\circ} \times \frac{2\pi}{360^{\circ}} \\ &\approx 2.22\end{aligned}$ .

The formula $s = r\, \theta$ relates the arc length $s$ of a sector of angle $\theta$ (in radians) to the radius $r$ of this sector.

In this question, it is given that the arc length of this sector is $s = 36\; \rm mm$ . It was found that $\theta = 2.22$ radians. Rearrange the equation $s = r\, \theta$ to find the radius $r$ of this sector:

$\begin{aligned} r&= \frac{s}{\theta} \\ &\approx \frac{36\; \rm mm}{2.22} \\ &\approx 16.2\; \rm mm\end{aligned}$ .

The perimeter of this sector would be:

$\begin{aligned}& 2\, r + s \\ =\; & 2 \times 16.2\; {\rm mm} + 36\; {\rm mm} \\ =\; & 68.5\; \rm mm\end{aligned}$ .

8 0

2 years ago

1. Two object accumulated a charge of

In-s [12.5K]

Answer:

The magnitude of the electric force between these two objects

will be: 181.274 N.

i.e. F $=181.274$ N

Step-by-step explanation:

As

Two object accumulated a charge of 4.5 μC and another a charge of 2.8 μC.

so

q₁ = 4.5 μC = 4.5 × 10⁻⁶ C

q₂ = 2.8 μC = 2.8 × 10⁻⁶ C

separated distance = d = 2.5 cm

Calculating the magnitude of the force between two charged objects using the formula:

$F = \frac{1}{4\pi \epsilon_0}\frac{q_1 q_2}{r^2}$

$=\:\frac{4.5\times \:\:10^{-6}\:\times \:\:2.8\:\times \:\:10^{-6}}{4\:\times \:\left(3.14\right)\:\times \:\left(8.85\times \:10^{-12}\right)\times \left(2.5\times \:\:10^{-2}\right)^2}$

$=\frac{10^{-12}\times \:12.6}{10^{-12}\times \:4\times \:8.85\pi \left(10^{-2}\times \:2.5\right)^2}$ ∵ $4.5\times \:10^{-6}\times \:2.8\times \:10^{-6}=10^{-12}\times \:12.6$

$=\frac{10^{-12}\times \:12.6}{10^{-12}\times \:35.4\pi \left(10^{-2}\times \:2.5\right)^2}$ ∵ $\mathrm{Multiply\:the\:numbers:}\:4\times \:8.85=35.4$

$\mathrm{Cancel\:the\:common\:factor:}\:10^{-12}$

$=\frac{12.6}{35.4\pi \left(10^{-2}\times \:2.5\right)^2}$

$=\frac{12.6}{0.025^2\times \:35.4\pi }$ ∵ $\left(10^{-2}\times \:2.5\right)^2=0.025^2$

$=\frac{12.6}{0.022125\pi }$ ∵ $35.4\pi\times 0.025^2=0.022125\pi$

$=\frac{12.6}{0.06950 }$

F $=181.274$ N

Therefore, the magnitude of the electric force between these two objects will be: 181.274 N.

i.e. F $=181.274$ N

7 0

3 years ago

The fair spinner shown in the diagram above is spun.

julsineya [31]

Answer:

1/5

Explanation:

There are five choices in the spinner. One of the choices is labeled '5'. That means you will have one out of the 5 choices to get the choice labeled '5'.

Good day :)

8 0

2 years ago

5m + 2[m+8] + 3 pls give answer m = 2

abruzzese [7]

So m=2, wherever m is put a 2

5x2+2(2+8)+3

Then do bidmas

Brackets-

5x2+2x10+3

Multiplication-

10+20+3

Addition-

33

Answer:33

7 0

3 years ago

If SDE ~ SWT, find WT.

faust18 [17]

Formula used: 40+x = 4x-3 x is used for ET

Step-by-step explanation:

40+x = 4x-3

+3 +3

43+x = 4x

-x -x

43 = 3x

3 3

14.3 = x

then substitude this on 5x+3 on WT and you arr good

5 0

3 years ago