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ArbitrLikvidat [17]
3 years ago
9

I cant figure out what is 4×(3x+5

Mathematics
2 answers:
adoni [48]3 years ago
6 0

Answer:

12x+20

Step-by-step explanation:

Just expand the brackets

damaskus [11]3 years ago
6 0

you have to do 12x+20.

hope this works

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If the area A of a triangle is 60sq m (square meters) and the base b is 20m (meters) what is the altitude of h
umka2103 [35]

Answer:

<u>The altitude or height of the triangle is 6 meters.</u>

Step-by-step explanation:

1. Let's review the information provided to us to answer the question correctly:

Area of a triangle = 60 m²

Base = 20 m

2. What is the altitude (h) of the triangle?

Let's recall that the formula of the area of a triangle is:

Area = (Base * Height)/2

Replacing with the real values, we have:

60 = (20 * Height)/2

60 * 2 = (20 * Height) (Multiplying by 2 at both sides)

120 = 20 Height

Height = 120/20 = 6 meters

<u>The altitude or height of the triangle is 6 meters.</u>

8 0
3 years ago
PLEASE HELP THIS IS VERY IMPORTANT I WILL GIVE U BRAIN THING IF ITS CORRECT AND IT SAYS WRITE YOUR REASON AS A DECIMAL SO PWEASE
lozanna [386]

Answer:

its, 4.4

Step-by-step explanation:

5 0
3 years ago
a soccar team spent $55 dollars on supplies for a car wash then earned $275 whats their total after paying for supplies
IrinaK [193]
To find what profit they made, subtract what they earned from what they spent money on. 275-55=220. They made a total of $220 after paying for supplies. I hope this helps! :)
8 0
3 years ago
IMMEDIATELY I NEED THIS DONE IN FIVE MINUTES Match the values with the equivalent percentages.
makkiz [27]

Answer:

35% of 150=52.5

20% of 50=10

10% of 20=2

45% of 200=90

6 0
2 years ago
Find the extreme values of f(x y)=xy subject to the constraint x^2 + y^2 -4 = 0
KATRIN_1 [288]
Via Lagrange multipliers:

L(x,y,\lambda)=xy+\lambda(x^2+y^2-4)

L_x=y+2\lambda x=0
L_y=x+2\lambda y=0
L_\lambda=x^2+y^2-4=0

yL_x=y^2+2\lambda xy=0
xL_y=x^2+2\lambda xy=0
\implies yL_x-xL_y=y^2-x^2=0\implies y^2=x^2
\implies x^2+y^2=4=2x^2\implies x^2=2\implies x=\pm\sqrt2\implies y=\pm\sqrt2

So we have four critical points to consider, (\sqrt2,\sqrt2),(-\sqrt2,\sqrt2),(\sqrt2,-\sqrt2),(-\sqrt2,-\sqrt2). If both coordinates are positive or both are negative, we get a maximum value of (\pm\sqrt2)^2=2; otherwise, we get a minimum of (-\sqrt2)(\sqrt2)=-2.
4 0
3 years ago
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