Need help plotting x and y intercept heres a better explanation of what I need to do

SOMEONE PLEASE HELP ME I WILLG IVE EVERYTHING!

Anvisha [2.4K]

Answer:

<h2>AB is around 33.18</h2><h2>BC is around 15.58 </h2>

Step-by-step explanation:

adjacent/hypotenuse is sine:

cos(28 degrees)=29.3/x

cos(28 degrees)*x=29.3

x=29.3/cos(28 degrees)

x=around 33.18

AB is around 33.18

opposite/adjacent is tangent

tan(28 degrees)=x/29.3

tan(28 degrees)*29.3=x

x=tan(28 degrees)*29.3

x=around 15.58

BC is around 15.58

4 0

4 years ago

In the Cartesian Coordinate System, the intersection of the axis is called the origin. What is this called in the Polar coordina

Nookie1986 [14]

it's plural so axes*

and in pilar coordinates, the axes are circular so they never intersect but the centre point is still called origin.

4 0

3 years ago

A government report gives a 99% confidence interval for the proportion of welfare recipients who have been receiving welfare ben

juin [17]

Answer:

The estimation for the proportion for this case is $\hat p = 0.21$

And we know that the 99% confidence interval is given by:

$0.21 \pm 0.045$

So then the margin of error at 99% of confidence is 0.045, and the margin of error is given by this formula:

$ME= z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

If we decrease the confidence level this margin of error can't be higher than 0.045 so then the correct answer for this case would be:

d. 21% ± 4.8%

Because if the z value decrease from 2.58 to 1.96 not makes sense that the margin of error increase from 0.045(4.5%) to 0.048(4.8%)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Solution to the problem

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})$

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

For the 99% confidence interval the value of $\alpha=1-0.99=0.01$ and $\alpha/2=0.005$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=2.58$

The estimation for the proportion for this case is $\hat p = 0.21$

And we know that the 99% confidence interval is given by:

$0.21 \pm 0.045$

So then the margin of error at 99% of confidence is 0.045, and the margin of error is given by this formula:

$ME= z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

If we decrease the confidence level this margin of error can't be higher than 0.045 so then the correct answer for this case would be:

d. 21% ± 4.8%

Because if the z value decrease from 2.58 to 1.96 not makes sense that the margin of error increase from 0.045(4.5%) to 0.048(4.8%)

5 0

3 years ago

Help me with the question in the pic please and thank u!

Zepler [3.9K]

Answer:

1.98

Step-by-step explanation:

In this problem, we are:

Given: ∠D = 26°, Hypotenuse (DF) = 4.5

To solve: EF

Now through the given, we are to focus on point D to solve for EF.

We need to find the relationship of point D to DF and EF.

The relationship here is sine.

Reason: $\frac{opposite}{hypotenuse}$

Through point D, DF is the hypotenuse and EF is the opposite side.

So let's solve this simply through algebra,

sin = $\frac{opposite}{hypotenuse}$

sin(26°) = $\frac{EF}{4.5}$

0.44 = $\frac{EF}{4.5}$

0.44 × 4.5 = EF

1.98 = EF

7 0

4 years ago

Write an equation of the line that passes through 3,1 and 0,10

elena-14-01-66 [18.8K]

Answer:y = -3x + 10

Step-by-step explanation:

To find an equation of a line that passes through two points, we have to first find the slope between the two equation. We can do this by using the slope formula:

where (x₁, y₁) and (x₂, y₂) are the two points that we are finding the slope between.

Lets make (x₁, y₁) equal to (0, 10) and (x₂, y₂) equal to (3, 1). Now we plug them into the slope formula:

So the slope between the two points is -3.

From here, I would normally take one of the points given to us and plug in the point and slope into the point-slope form of a line and then simplify until we get it in slope-intercept form. But if you look carefully, the y-intercept is given to us as the point (0, 10). So we now know that the y-intercept of the line is 10. We can now take the y-intercept and the slope and plug it into the slope-intercept form of a line to get out equation:

y = mx + b

plug in -3 for m (the slope) and 10 for b (the y-intercept)

y = -3x + 10

So now we have our equation.

I hope you find my answer and explanation helpful. Happy studying. :)

3 0

3 years ago