Answer:Answer: y=x/3−2.
Step-by-step explanation:
find the equation of the line perpendicular to the line y=2−3x passing through the point (3,−1).
The equation of the line in the slope-intercept form is y=2−3x.
The slope of the perpendicular line is negative inverse: m=13.
So, the equation of the perpendicular line is y=x3+a.
To find a, we use the fact that the line should pass through the given point: −1=(13)⋅(3)+a.
Thus, a=−2.
Therefore, the equation of the line is y=x3−2.
Answer: y=x/3−2.
check the picture below.
the line QS is just a flat-line and therefore it has 180° on either side, so the angle QPR is 57°, as you see there, and since we know the diameter is 20, that simply means the radius of the circle is 10.
The Romans no longer feared him after his death in 453.
Let the year be represented by = x
So, inequality becomes -
453<x ; x will be smaller than 453 because Hun was dead in 453. So 453 and any number smaller than that would be the times in his life that he would have been feared.
Answer:
y>0.5
Step-by-step explanation:
Rearrange the equation so "y" is on the left and everything else on the right.
Plot the "y=" line (make it a solid line for y≤ or y≥, and a dashed line for y< or y>
Shade above the line for a "greater than" (y> or y≥)
or below the line for a "less than" (y< or y≤).
y+x>1
-y -y
x>1-y
2x+y<3
-y -y
2x<3-y
divide by 2
x<1.5-y/2
1.5-y/2>1-y
-1.5+y -1.5+y
<u>y>0.5</u>
Answer:
n^2 + 2n.
Step-by-step explanation:
n = 1 2 3 4 5
term t = 3 8 15 24 35
Diffs = 5 7 9 11
2 2 2 - so the nth term contains n^2.
n^2 = 1 4 9 16 25
t - n^2 = 2 4 6 8 10
This is an arithmetic sequence with nth term = 2 + (n-1)2 = 2n
So the nth term of the quadratic sequence = n^2 + 2n.
