First you do 6-3 which is 3 then divide it by 18 which is 6 then add it by 7 which is 13
Assume (a,b) has a minimum element m.
m is in the interval so a < m < b.
a < m
Adding a to both sides,
2a < a + m
Adding m to both sides of the first inequality,
a + m < 2m
So
2a < a+m < 2m
a < (a+m)/2 < m < b
Since the average (a+m)/2 is in the range (a,b) and less than m, that contradicts our assumption that m is the minimum. So we conclude there is no minimum since given any purported minimum we can always compute something smaller in the range.
Answer: y = 90 x = 29
Step-by-step explanation:
Answer:
6. D
7. B
Step-by-step explanation:
Nancy takes a test that has two sections: essay and true/false. She scores 56 points on the essay. Each true/false question is 4 points. So x number of true/false is worth 4 points each or 4x.
Together her score will be 56 + 4x.
She wants to score more than 80 or > 80.
So her test can be represented as the inequality 56 + 4x > 80.
This is solved using inverse operations.
56 + 4x > 80
4x > 24
x > 6
This should be graphed as an open circle at 6 on the umber line pointing and shaded to the the right for numbers greater than 6.
<span>y=-11x-8
11x + y = -8 ...this is standard form
hope it helps</span>
