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AVprozaik [17]
3 years ago
6

A CHICKEN COOP HOLDS A TOTAL OF 10 HENS OR 20 CHICKS. IF 2/5THS OF THE HENS IN A FULL COOP ARE REMOVED, HOW MANY NEW CHICKS COUL

D FIT IN THE CHICKEN COOP?
Mathematics
1 answer:
LiRa [457]3 years ago
5 0

Answer:

8 new chicks can be fitted in the coop.

Step-by-step explanation:

A chicken coop holds 10 hens or 20 chicks.

That means space in the coop for 10 hens = space for 20 chicks

Or space for 1 hen = space for 2 chicks

Now \frac{2}{5}th of the hens were removed from the coop.

So, number of hens removed from the coop = \frac{2}{5}\times 10

= 4 hens

And space for 4 hens in the coop = space for the 8 chicks

Therefore, 8 new chicks can be fitted in the coop.

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Hello,

Reminders:
$\sum_{i=1}^{n} i= \dfrac{n(n+1)}{2}$



$ \sum_{i=1}^{n} i^2= \dfrac{n(n+1)}{2}$


$ \sum_{i=1}^{n} i^3= \dfrac{n^2(n+1)^2}{4} $


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$= \dfrac{1}{2}\sum_{i=1}^{6}  (\frac{i^3}{8} -6i)=\dfrac{1}{16}*\frac{(6*7)^2}{4}- \frac{9*7}{2}= -3.9575


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Step-by-step explanation:

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