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AVprozaik [17]
3 years ago
6

A CHICKEN COOP HOLDS A TOTAL OF 10 HENS OR 20 CHICKS. IF 2/5THS OF THE HENS IN A FULL COOP ARE REMOVED, HOW MANY NEW CHICKS COUL

D FIT IN THE CHICKEN COOP?
Mathematics
1 answer:
LiRa [457]3 years ago
5 0

Answer:

8 new chicks can be fitted in the coop.

Step-by-step explanation:

A chicken coop holds 10 hens or 20 chicks.

That means space in the coop for 10 hens = space for 20 chicks

Or space for 1 hen = space for 2 chicks

Now \frac{2}{5}th of the hens were removed from the coop.

So, number of hens removed from the coop = \frac{2}{5}\times 10

= 4 hens

And space for 4 hens in the coop = space for the 8 chicks

Therefore, 8 new chicks can be fitted in the coop.

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Step-by-step explanation:

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3 years ago
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tiny-mole [99]

Answer:

24 as the denominator.

Step-by-step explanation:

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3 years ago
Explain how you can use base ten blocks to find 1.54+ 2.37
solong [7]
0.00

*First column to your left - ones column (1)
*Column just after decimal place, in the middle - tenths column (1/10)
*Column to the far right - hundredths column (1/100)

The only numbers that can go in these columns are 0-9.

-------------

1.54 + 2.37 

= (1 + 5/10 + 4/100) + (2 + 3/10 + 7/100)

= 1 + 5/10 + 4/100 + 2 + 3/10 + 7/100

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= 3 + 8/10 + 1/10 + 1/100

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6 0
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