The two factors of a quadratic equation can be multiplied to form the original equation. Let the missing term be a:
y² + 15y + 56 = (y + 7)(y + a)
y² + 15y + 56 = y² + (7 + a)y + 7a
We can now compare the coefficient of the like terms, either the one with y or the one without y, and find the value of a.
15 = 7 + a; a = 8
OR
56 = 7a; a = 8
Second factor is (y + 8)
Answer:
(1, 4) and (1,3), because they have the same x-value
Step-by-step explanation:
For a relation to be regarded as a function, there should be no two y-values assigned to an x-value. However, two different x-values can have the same y-values.
In the relation given in the equation, the ordered pairs (1,4) and (1,3), prevent the relation from being a function because, two y-values were assigned to the same x-value. x = 1, is having y = 4, and 3 respectively.
Therefore, the relation is not a function anymore if both ordered pairs are included.
<em>The ordered pairs which make the relation not to be a function are: "(1, 4) and (1,3), because they have the same x-value".</em>
Okay this is simple once you get use to it. What you first need to do is figure out the formula. I don’t have a calculator on me so I will just tell you the formula so you can get the answer
: 1/3 times 8 times 6 times 10
The answer is 80 because 800÷10=80
