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Mekhanik [1.2K]
3 years ago
5

20 POINTS FOR ONE QUESTION!!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
SCORPION-xisa [38]3 years ago
3 0
A. Sometimes true.....
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Bad White [126]
Since it’s in the tenths place it’s 50
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3 years ago
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Evaluate the expression using x = -6 and y= 3
FinnZ [79.3K]

Answer:

-45

Step-by-step explanation:

put x = -6 and y=3 in this expression : y(2x - y)

3(2(-6)-3) = 3(-12 -3)= 3(-15) = -45

6 0
3 years ago
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Simplify. (-2)-3 -8 - 8 user: simplify. 6x-2
Vinvika [58]
If you would like to simplify <span>(-2)-3 -8 - 8 and 6x - 2, you can do this using the following steps:

</span><span>(-2)-3 -8 - 8 = - 2 - 3 - 8 - 8 = - 5 - 8 - 8 = - 13 - 8 = - 21

6x - 2 = 2 * (3x - 1)

The correct result would be - 21 and </span><span>2 * (3x - 1).</span>
3 0
3 years ago
Customers of a phone company can choose between two service plans for long distance calls. The first plan has a $22 monthly fee
vladimir2022 [97]
Company a = 22 + 0.07m
company b = 8 + 0.12m

We are looking for the time when the prices are equal. i.e. the price of company a = the price of company b

company a = company b
22 + 0.07m = 8 + 0.12m
22 - 8 = 0.12m - 0.07m
14 = 0.05m
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Therefore, the two companies will cost the same if you talk for 280 minutes
5 0
3 years ago
20 points! Will mark the brainliest!
andrew-mc [135]
\dfrac{ \dfrac{x+3}{4x^2-16} }{ \dfrac{2x^2+10x+12}{2x-4} }

-----------------------------------------------------------------------------------
Write the divide fraction horizontally:
-----------------------------------------------------------------------------------

= \dfrac{x+3}{4x^2-16} \div \dfrac{2x^2+10x+12}{2x-4}

-----------------------------------------------------------------------------------
Factorise the numerators and denominators when possible:
-----------------------------------------------------------------------------------

= \dfrac{x+3}{4(x+2)(x-2)} \div \dfrac{ 2(x + 3) (x + 2)}{2(x-2)}

-----------------------------------------------------------------------------------
Convert the divide fraction to multiplication fraction
-----------------------------------------------------------------------------------

= \dfrac{x+3}{4(x+2)(x-2)} \times \dfrac{2(x-2)}{2(x+3)(x+2)}

-----------------------------------------------------------------------------------
Cancel the factors
-----------------------------------------------------------------------------------
= \dfrac{1}{4(x+2)} \times \dfrac{1}{(x+2)}

-----------------------------------------------------------------------------------
Combine to single fraction
-----------------------------------------------------------------------------------

= \dfrac{1}{4(x+2)^2}



4 0
3 years ago
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