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raketka [301]
2 years ago
10

What’s the square root of -5

Mathematics
1 answer:
Arte-miy333 [17]2 years ago
6 0

Answer:

Square Root =2.2361.

Square Value =25.

Step-by-step explanation:


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Please help me out :( these confuse me
Pavel [41]

Answer:

The answer to your question is : 33.3 (Rounded).

Step-by-step explanation:

I got this answer by dividing 19.6 by 20, which gave me 0.98.

Then, I multiplied 0.98 by 34, which gave me 33.32.

After rounding, 33.3 is your answer.

Hope this helped!!

8 0
3 years ago
Read 2 more answers
Twice the difference of a number and 2 is at most -27
igor_vitrenko [27]
<h2>Explanation:</h2><h2 />

When we say "a is at most b" we mean that "a is less than or equal to b" or "a is not greater than b". So let's solve this problem as follows:

Step 1. Twice the difference of a number and 2

Let's call that unknown number as n. Then, twice the difference of a number and 2 is:

2(n-2)

Step 2. Twice the difference of a number and 2 is at most -27

2(n-2)\leq -27

_________________________________________

So the mathematical form of the statement <em>twice the difference of a number and 2 is at most -27 </em>is:

\boxed{2(n-2)\leq -27}

5 0
3 years ago
Need help with this please
Studentka2010 [4]

Answer:

.

Step-by-step explanation:

7 0
2 years ago
What is the answer to this question? 1 + 5?
BartSMP [9]
I dont know

girly but hopefully u find the right answer

8 0
3 years ago
Element X decays radioactively with a half life of 12 minutes. If there are 200 grams of Element X, how long, to the nearest ten
Semenov [28]

Answer:

It would take 24 minutes for the element to decay to 50 grams

Step-by-step explanation:

The equation for the amount of the element present, after t minutes, is:

Q(t) = Q(0)e^{-rt}

In which Q(X) decays radioactively with a half life of 12 minutes.(0) is the initial amount and r is the rate it decreases.

Half life of 12 minutes

This means that Q(12) = 0.5Q(0)

So

Q(t) = Q(0)e^{-rt}

0.5Q(0) = Q(0)e^{-12r}

e^{-12r} = 0.5

\ln{e^{-12r}} = \ln{0.5}

-12r = \ln{0.5}

12r = -\ln{0.5}

r = -\frac{\ln{0.5}}{12}

r = 0.05776

If there are 200 grams of Element X, how long, to the nearest tenth of a minute, would it take the element to decay to 50 grams?

This is t when Q(t) = 50. Q(0) = 200.

Q(t) = Q(0)e^{-rt}

50 = 200e^{-0.05776t}

e^{-0.05776t} = 0.25

\ln{e^{-0.05776t}} = \ln{0.25}

-0.05776t = \ln{0.25}

0.05776t = -\ln{0.25}

t = -\frac{\ln{0.25}}{0.05776}

t = 24

It would take 24 minutes for the element to decay to 50 grams

6 0
3 years ago
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