Answer:
25*3*8=600
Step-by-step explanation:
25 students has 3 markrers for each then 25*3 is 75, after that marker come in packages of 8,so 75*8 is 600 packages.
Answer:
1 2/3
Step-by-step explanation:
Given :
Find the sum of 1/2, 4 /8 and 2 /3
1/2 + 4/8 + 2/3
L.c.m = 24
(12 + 12 + 16) / 24
40 / 24
= 1 16/24
= 1 2/3
Answer:
x=5
Step-by-step explanation:
Since 32 is 8 times 4 cm, then 40/8=5.
Answer:
The area of the pyramid’s base is 36 in².
The pyramid has 4 lateral faces.
The surface area of each lateral face is 27 in².
Step-by-step explanation:
"<u>Lateral</u>" means side, so the lateral faces are <u>triangles</u>.
The <u>base</u> is the bottom, which is a <u>square</u>.
To calculate the <u>area of the base</u>, use the formula for area of a square.
![A_{base} = s^{2}](https://tex.z-dn.net/?f=A_%7Bbase%7D%20%3D%20s%5E%7B2%7D)
![A_{base} = (6 in)^{2}](https://tex.z-dn.net/?f=A_%7Bbase%7D%20%3D%20%286%20in%29%5E%7B2%7D)
![A_{base} = 36 in^{2}](https://tex.z-dn.net/?f=A_%7Bbase%7D%20%3D%2036%20in%5E%7B2%7D)
To calculate the <u>area of a lateral face</u>, find the area of a triangle.
![A_{lateral} = \frac{bh}{2}](https://tex.z-dn.net/?f=A_%7Blateral%7D%20%3D%20%5Cfrac%7Bbh%7D%7B2%7D)
![A_{lateral} = \frac{(6 in)(9 in)}{2}](https://tex.z-dn.net/?f=A_%7Blateral%7D%20%3D%20%5Cfrac%7B%286%20in%29%289%20in%29%7D%7B2%7D)
![A_{lateral} = \frac{54 in^{2}}{2}](https://tex.z-dn.net/?f=A_%7Blateral%7D%20%3D%20%5Cfrac%7B54%20in%5E%7B2%7D%7D%7B2%7D)
![A_{lateral} = 27 in^{2}](https://tex.z-dn.net/?f=A_%7Blateral%7D%20%3D%2027%20in%5E%7B2%7D)
In a pyramid, the number of lateral faces is the same as the number of sides in the base. <u>The square base as 4 sides, so there are 4 lateral faces</u>.
Tan205° = .466 tan55° = 1.428 tan25° = .466 -tan25° = " so just tan25