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Ann [662]
3 years ago
13

Lainey bought a set of 20 markers for 6 dollars​

Mathematics
2 answers:
jeka943 years ago
7 0

Answer:

$3.33

Step-by-step explanation:

Divide 20 by 6

Tasya [4]3 years ago
3 0
The answer is $3.33

explanation: divide 20 by 6 which gets you $3.33
to check that you can multiply 3.33 and 6 which gets you 19.98 and u round up because the 3.33 is continuous
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Need answer thanks! only answer if you know please​!
Vaselesa [24]

Answer:

a) k \approx 0.0602\,\frac{1}{min} (k\approx  6.02\,\frac{\%}{min}), b) k \approx 0.0648\,\frac{1}{min} (k \approx 6.48\,\frac{\%}{min}), c) t_{1/2} \approx 60.274\,days, d) t_{1/2}\approx 4.305\,min, e) k \approx 0.3\,\frac{1}{min} (k\approx 30\,\frac{\%}{min}), f) k \approx 0.0120\,\frac{1}{min} (k \approx 1.20\,\frac{\%}{min}), g) k \approx 2.876\times 10^{-5}\,\frac{1}{yr} (k \approx 2.876\times 10^{-3}\,\frac{\%}{yr})

Step-by-step explanation:

All radioactive isotopes decay exponentially, the mass of the isotope as a function of time (m(t)), measured in grams, is defined by:

m(t) = m_{o}\cdot e^{-k\cdot t} (1)

Where:

m_{o} - Initial mass of the isotope, measured in grams.

k - Decay rate, measured in \frac{1}{min} or \frac{1}{day} or \frac{1}{yr}.

t - Time, measured in minutes, days or years.

We define the decay rate in terms of half-life by using the following expression:

k = \frac{\ln 2}{t_{1/2}} (2)

Where t_{1/2} is the half-life of the isotope, measured in minutes or years.

Now we proceed to determine the missing values:

a) Polonium-200 (t_{1/2} = 11.5\,min)

k = \frac{\ln 2}{11.5\,min}

k \approx 0.0602\,\frac{1}{min}

b) Lead-194 (t_{1/2} = 10.7\,min)

k = \frac{\ln 2}{10.7\,min}

k \approx 0.0648\,\frac{1}{min}

c) Iodine-125 (k = 0.0115\,\frac{1}{day})

t_{1/2} = \frac{\ln 2}{k}

t_{1/2} = \frac{\ln 2}{0.0115\,\frac{1}{day} }

t_{1/2} \approx 60.274\,days

d) Kryption-75 (k = 0.161\,\frac{1}{min})

t_{1/2} = \frac{\ln 2}{k}

t_{1/2} = \frac{\ln 2}{0.161\,\frac{1}{min} }

t_{1/2}\approx 4.305\,min

e) Strontium-79 (t_{1/2} = 2.3\,min)

k = \frac{\ln 2}{2.3\,min}

k \approx 0.3\,\frac{1}{min}

f) Uranium-229 (t_{1/2} = 58\,min)

k = \frac{\ln 2}{58\,min}

k \approx 0.0120\,\frac{1}{min}

g) Plutonium-239 (t_{1/2} = 24100\,yr)

k = \frac{\ln 2}{24100\,yr}

k \approx 2.876\times 10^{-5}\,\frac{1}{yr}

6 0
3 years ago
Which relation is a function? choose all the correct answers. pls help asap!
Sonja [21]

It's the second one

An input can only have one output, an output can have multiple inputs though

4 0
2 years ago
Read 2 more answers
What is the volume of a rectangular prism with the length of 4.5 ft, the width of 3.5 ft, and the height of 5.5 ft?
sdas [7]

Answer:

The volume would be 86.63 feet squared

Hope this helps!

Mark me brainliest if I'm right :)

8 0
3 years ago
Kennedy is working two summer jobs, making $11 per hour babysitting and making $8 per hour clearing tables. In a given week, she
VARVARA [1.3K]
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| x+y(less than or equal to)17
| 11x+8y(greater than or equal to)160
~

5 0
3 years ago
A lake near the Arctic Circle is covered by a 222-meter-thick sheet of ice during the cold winter months. When spring arrives, t
STatiana [176]

Answer:

S(t) = 2 - 0.25*t

Step-by-step explanation:

A lake near the Arctic Circle is covered by a 2-meter-thick sheet of ice during the cold winter months.

When spring arrives, the warm air gradually melts the ice, causing its thickness to decrease at a constant rate.

S(t) denote the ice sheet's thickness S ( measured in meters) as a function of time (measured in weeks).

Therefore the equation formed will be linear.

The equation will be of the form y = mx + b

Here S(t) = mt + b

Here m is the slope which is the rate at which ice is melting.

Putting t = 0

S(t) = 2

Putting t = 3,

S(t) = 1.25

Therefore, m*0 + b = 2 or, b = 2

and 3m + b = 1.25

or, 3m = 1.25 - 2 = -0.75

or, t = -0.25

Hence, function's formula = S(t) = -0.25*t + 2

i.e. S(t) = 2 - 0.25*t

5 0
3 years ago
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