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Dvinal [7]
3 years ago
8

Consider the following.

Mathematics
1 answer:
Fantom [35]3 years ago
5 0

Answer:

(-8, 7); x + y = 13 → y= -x + 13

parallel lines have the same slope. slope is -1

y = -x + b

7 = -(-8) + b

7 = 8 + b

b = -1

(a) y = -x - 1

perpendicular lines have opposite slopes. slope is 1/2.

y = -1/2x + b

7 = -1/2(-8) + b

7 = 4 + b

b = 3

(b) y = -1/2x + 3

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La ecuación de la recta que lasa a través de los puntos P1 (2,5) y P2 (4,11) es: a) 3x+y+1=0 b)3x-y-1=0 c) 3x-y+1=0
Zolol [24]

Respuesta:

3x-y-1 = 0

Explicación paso a paso:

La forma estándar de ecuación de una línea se expresa como y = mx + b

M es la pendiente

b es la intersección con el eje y

Dada la coordenada P1 (2,5) y P2 (4,11)

Pendiente m = y2-y1 / x2-x1

m = 11-5 / 4-2

m = 6/2

m = 3

Sustituya m = 3 y (2,5) en y = mx + b

5 = 3 (2) + b

5 = 6 + b

b = 5-6

b = -1

Obtén la ecuación

y = 3x-1

Igualar a cero

y - 3x +1 = 0

Multiplicar por -1

3x-y-1 = 0

Esto da la ecuación requerida

5 0
3 years ago
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Nikitich [7]

Answer:

x<32

Step-by-step explanation:

3 0
3 years ago
Question 1 options:<br><br> 68°<br><br> 136°<br><br> 158°<br><br> 112°
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Answer:

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Step-by-step explanation:

Opposite angles in an inscribed quadrilateral are supplementary.

∠P = 180° -∠R = 180° -68°

∠P = 112°

6 0
3 years ago
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Answer: 27.12


Step-by-step explanation:

32.01

-5.89

27.12

6 0
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