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3 years ago

Unit test Which of the x-values are solutions to the following inequality? 2 > 111

Mathematics

1 answer:

MrRissso [65]3 years ago

8 0

Answer: C

Step-by-step explanation: It is C because X is greater than (>) 111, and 119 is greater than 111. Good luck on the test!

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Help me with differentation and integration please!!

Marina86 [1]

Answer:

See below

Step-by-step explanation:

$\dfrac{d}{dx} (\tan^3 x) = 3\sec^4 x - 3\sec^2 x$

Recall

$\dfrac{d}{dx}\tan x=\sec^2$

Using the chain rule

$\dfrac{dy}{dx}= \dfrac{dy}{du} \dfrac{du}{dx}$

such that $u = \tan x$

we can get a general formulation for

$y = \tan^n x$

Considering the power rule

$\boxed{\dfrac{d}{dx} x^n = nx^{n-1}}$

we have

$\dfrac{dy}{dx} =n u^{n-1} \sec^2 x \implies \dfrac{dy}{dx} =n \tan^{n-1} \sec^2 x$

therefore,

$\dfrac{d}{dx}\tan^3 x=3\tan^2x \sec^2x$

Now, once

$\sec^2 x - 1= \tan^2x$

we have

$3\tan^2x \sec^2x = 3(\sec^2 x - 1) \sec^2x = 3\sec^4x-3\sec^2x$

Hence, we showed

$\dfrac{d}{dx} (\tan^3 x) = 3\sec^4 x - 3\sec^2 x$

================================================

For the integration,

$\int \sec^4 x\, dx$

considering the previous part, we will use the identity

$\boxed{\sec^2 x - 1= \tan^2x}$

thus

$\int\sec^4x\,dx=\int \sec^2 x(\tan^2x+1)\,dx = \int \sec^2 x \tan^2x+\sec^2 x\,dx$

and

$\int \sec^2 x \tan^2x+\sec^2 x\,dx = \int \sec^2 x \tan^2x\,dx + \int \sec^2 x\,dx$

Considering $u = \tan x$

and then $du=\sec^2x\ dx$

we have

$\int u^2 \, du = \dfrac{u^3}{3}+C$

Therefore,

$\int \sec^2 x \tan^2x\,dx + \int \sec^2 x\,dx = \dfrac{\tan^3 x}{3}+\tan x + C$

$\boxed{\int \sec^4 x\, dx = \dfrac{\tan^3 x}{3}+\tan x + C }$

6 0

3 years ago

Alice tyre pressure gauge shows a reading which is 8% lower than actual pressure

olasank [31]

Answer:

30.8936

Step-by-step explanation:

Pressure guage reading is 8% lower than tbe actual pressure.

Therefore, for a tyre with guage pressure, 33.58 ;

The actual pressure of tyre would be :

Guage pressure - 8% of guage pressure

33.58 - (0.08 * 33.58)

33.58 - 2.6864

= 30.8936

Actual pressure = 30.8936

3 0

3 years ago

Why do non STEM majors detest taking algebraic courses at the collegiate level?

yKpoI14uk [10]

Answer:

Because they find it hard to pass in the past.

Step-by-step explanation:

Non-STEM majors detest taking algebraic courses at the collegiate level because based on their past experiences in high school, whereby they probably do not excel in algebra, numbers, or mathematical subjects in general, the thought of going through advanced numbers and equations can be overwhelming.

Nobody wants to have or at least start college with poor grades. Hence, because non-STEM students find algebraic courses hard to pass in the past, they detest taking the course that has to do with it at the college level.

7 0

3 years ago

I need help please and thank you

nasty-shy [4]

Answer:

x=28

Step-by-step explanation:

x-4 =8(3)

x-4 =24

x= 28

7 0

3 years ago