Answer:
look below
Step-by-step explanation:
72.3 = 70 + 2 + .3
7.023 = 7 + .02 + .003
.723 = .7 + .02 + .003
Hopefully this helps you :)
pls mark brainlest ;)
Answer:
A = 29
Step-by-step explanation:
a triangle is equal to 180 so the bottom triangle you add 34 + 26 = 60 --> 180-60 = 120 ---> the triangle on top is 120 + 31 = 151 -----> 180-151 = 29
Answer:
y = 4
Step-by-step explanation:
Move all terms containing y to the left, all other terms to the right. Add '-2y' to each side of the equation.
-5 + 3y + -2y = -1 + 2y + -2y
Combine like terms: 3y + -2y = 1y
-5 + 1y = -1 + 2y + -2y
Combine like terms: 2y + -2y = 0
-5 + 1y = -1 + 0
-5 + 1y = -1
Add '5' to each side of the equation.
-5 + 5 + 1y = -1 + 5
Combine like terms: -5 + 5 = 0
0 + 1y = -1 + 5
1y = -1 + 5
Combine like terms: -1 + 5 = 4
1y = 4
Divide each side by '1'.
y = 4
Simplifying
y = 4
The best buy is the in. I really hope this helped
Answer:
x = {nπ -π/4, (4nπ -π)/16}
Step-by-step explanation:
It can be helpful to make use of the identities for angle sums and differences to rewrite the sum:
cos(3x) +sin(5x) = cos(4x -x) +sin(4x +x)
= cos(4x)cos(x) +sin(4x)sin(x) +sin(4x)cos(x) +cos(4x)sin(x)
= sin(x)(sin(4x) +cos(4x)) +cos(x)(sin(4x) +cos(4x))
= (sin(x) +cos(x))·(sin(4x) +cos(4x))
Each of the sums in this product is of the same form, so each can be simplified using the identity ...
sin(x) +cos(x) = √2·sin(x +π/4)
Then the given equation can be rewritten as ...
cos(3x) +sin(5x) = 0
2·sin(x +π/4)·sin(4x +π/4) = 0
Of course sin(x) = 0 for x = n·π, so these factors are zero when ...
sin(x +π/4) = 0 ⇒ x = nπ -π/4
sin(4x +π/4) = 0 ⇒ x = (nπ -π/4)/4 = (4nπ -π)/16
The solutions are ...
x ∈ {(n-1)π/4, (4n-1)π/16} . . . . . for any integer n
