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2 years ago

Simplify. Your answer should only contain only positive exponents.

Mathematics

2 answers:

Xelga [282]2 years ago

6 0

Answer:

Step-by-step explanation:

kow [346]2 years ago

6 0

Answer:

Step-by-step explanation:

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Sara has a gift box with a volume of 64 in3. The length, width, and height of the box are all y inches. Sara needs to determine

antoniya [11.8K]

Answer:

No, the note papers will not fit the gift box.

Step-by-step explanation:

Given that:

Volume of the gift box = 64 $in^3$

Length, width and height of the box all are equal to $y$ inches.

Dimensions of note papers = 6 inch by 6 inch

To determine:

Whether the note papers will fit the bottom of the box?

Solution:

Here, we need to find the dimensions of the gift box first.

If the dimensions of gift box are greater than or equal to the dimensions of the note papers, only then the papers will fit into the box.

As per the given question statement, the gift box is in the form of a cube.

Formula for volume of a cube is given as:

$Volume = (Side)^3$

Side is given equal to $y$ inches.

$64 = y^3\\\Rightarrow y = 4\ in$

Dimensions of the box are lesser than that of the note papers.

Therefore, <em>the note papers will not fit into the gift box</em>.

6 0

2 years ago

Rewrite p(x)=x³+3x²-4

valentinak56 [21]

Answer:

use symblaob

Step-by-step explanation:

on g_o_o_g_l_e

5 0

3 years ago

Read 2 more answers

Really really need this answer. Please help!

scZoUnD [109]

Use the cosine function.

cos x = 2/12
cos x = 0.167

use the inverse of cosine:

x = 80.405

The answer is C.

Hope this helps :)

4 0

3 years ago

Write the linear equation given two points (-6, 8) and (3, -7). *

horrorfan [7]

$\bf (\stackrel{x_1}{-6}~,~\stackrel{y_1}{8})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{-7}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-7}-\stackrel{y1}{8}}}{\underset{run} {\underset{x_2}{3}-\underset{x_1}{(-6)}}}\implies \cfrac{-15}{3+6}\implies \cfrac{-15}{9}\implies -\cfrac{5}{3}$

$\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{8}=\stackrel{m}{-\cfrac{5}{3}}[x-\stackrel{x_1}{(-6)}]\implies y-8=-\cfrac{5}{3}(x+6) \\\\\\ y-8=-\cfrac{5}{3}x-10\implies y = -\cfrac{5}{3}x-2$

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2 years ago

Please help giving all my points

Kay [80]

Answer:

Step-by-step explanation:

1. Subtraction

2.multiplication

6 0

2 years ago

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