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inna [77]
3 years ago
8

Please answer this correctly

Mathematics
1 answer:
prohojiy [21]3 years ago
6 0

Answer:

Hi there!

The answer to the answer to this question is: 1,399.286

Step-by-step explanation:

There is two methods you can solve this question, either with long division or short division in this case I chose short division and got 1,399.286

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I’ll mark as brainliest if someone can help me!!
yawa3891 [41]

Answer:

The answer is B

Step-by-step explanation:

because it snows 4 more time

if 30mins is 7/8 then 3

more of that is 4 times

8 0
3 years ago
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Does anyone know how to do this?
kozerog [31]
I know the answer to this
3 0
3 years ago
Sam read 2/5 of her book over the weekend and 1/6 of it on Monday. What fraction of the book has she read? What fraction of the
tiny-mole [99]
2/5 + 1/6 = 12+5/30 = 17/30
30/30 is the whole book so, 30/30 - 17/30 = 13/30
Sam had to read 13/30 of the book.
8 0
3 years ago
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the length of a rectangle is 5cm greater than the width. the area of the rectangle is 84cm squared. find the length and width
Ymorist [56]

Answer:

Therefore,

Length=12\ cm

Width= 7\ cm

Step-by-step explanation:

Let the Width of rectangle be 'x' cm.

Then the length of a rectangle will be (x + 5) cm.

Area of rectangle given is 84 cm squared.

To Find:

Length = (x+5) = ?

Width = x = ?

Solution:

We have area of rectangle given as

\textrm{Area of Rectangle}=Length\times Width

Substituting the given values we get

84=(x+5)x\\x^{2} +5x-84=0\\

On factorizing we get

x^{2} +12x-7x-84=0\\x(x+12)-7(x+12)=0\\(x+12)(x-7)=0\\(x+12)=0\ or\ (x-7)=0\\x=-12\ or\ x=7\\\therefore x =7\ cm\ \textrm{As x cannot be negative}

Therefore,

Length=x+5=7+5=12\ cm

Therefore,

Length=12\ cm

Width= 7\ cm

8 0
3 years ago
What is 4.345 × 10^5 in standard form?
alexandr1967 [171]
<h3>Answer:  434,500</h3>

You may need to erase the comma

To get this answer, move the decimal point to the right 5 spaces to go from 4.345 to 434,500

If the exponent was -5, then you would move five spaces to the left.

8 0
3 years ago
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