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skad [1K]
4 years ago
10

Math question any help is appreciated ! :)​

Mathematics
1 answer:
-Dominant- [34]4 years ago
6 0

Answer:

x=9y+127

y=79x+−43

Step-by-step explanation:

<em><u>steps</u></em><em><u> for x.</u></em>

3y−x3−2x=−4

Step 1: Add -3y to both sides.

−73x+3y+−3y=−4+−3y

−73x=−3y−4

Step 2: Divide both sides by (-7)/3.

−73x−73=−3y−4−73

x=9y+127

Answer:

x=9y+127

<em><u>steps</u></em><em><u> for y.</u></em>

3y−x3−2x=−4

Step 1: Add 7/3x to both sides.

−73x+3y+73x=−4+73x

3y=73x−4

Step 2: Divide both sides by 3.

3y3=73x−43

y=79x+−43

Answer:

y=79x+−43

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Answer:

Parabolas always have a lowest point (or a highest point, if the parabola is upside-down). This point, where the parabola changes direction, is called the "vertex". If the quadratic is written in the form y = a(x – h)2 + k, then the vertex is the point (h, k). This makes sense, if you think about it.

Step-by-step explanation:

8 0
3 years ago
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​Parallelogram ABCD​ is a rectangle. AC=2y+7 BD=3y−4 What is the value of y?
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Answer:

You didn't attach an image so I will assume that AC and BD are opposite sides. In a parallelogram, opposite sides are congruent which means:

2y + 7 = 3y - 4

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4 years ago
Answer PLS
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If 3 to the power y = x then y = ?
Oksanka [162]

Answer:

y=\log_3(x)


Step-by-step explanation:

3^y=x

\ln(3^y)=\ln(x)

y\ln(3)=\ln(x)

y=\frac{\displaystyle\ln(x)}{\displaystyle\ln(3)}

but if

f(x)=\frac{\displaystyle\ln(x)}{\displaystyle\ln(3)}

then since

f(3)=\frac{\displaystyle\ln(3)}{\displaystyle\ln(3)}=1

f(x)=\log_3(x)

so

y=\log_3(x)


or


3^y=x

\log_3(3^y)=\log_3(x)

y\log_3(3)=\log_3(x)

\text{but }\,\log_3(3)=1, \text{so,}

y=\log_3(x)



6 0
3 years ago
10 POINTS AND BRAINLIEST<br> Please answer all 3 questions attached correctly.
lana66690 [7]

Answer:

#1. Identity #2. 0 #3. No solution

Step-by-step explanation:

#1.

5y + 2 = (1/2)(10y+4)

5y + 2 = 5y + 2

This would be identity as the equation of the left and right are the same. This is not to be confused with no solution(explained below).

#2.

0.5b + 4 = 2(b+2)

0.5b + 4 = 2b + 4

0.5 b - 2b = 0

b = 0

#3.

-3x + 5 = -3x + 10

This equation has no solution because when you try to bring the -3x to one side, the x variable itself gets eliminated. So, how is it different from identity? Well in the first equation, it is true that when we try to bring the 5y one side it eliminates the y variable, however, that is also true for the constants(since if we try to bring the 2 to one side, it will be 2-2 which will equal 0, thus eliminating each other), but in this case, even if we remove the x, the constants will not equal 0, thus it will have no solution.

5 0
4 years ago
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