- Yes, the height, h(t) of a ball t seconds after it's dropped from the third floor of a building is a function.
- No, table B is not a function because no function can have the same y-values (5) for different x-values (1 and 8).
- Yes, table C is a function because it has different y-values for same x-values.
- Yes, graph D is a function because it has different y-values for same x-values.
<h3>What is a function?</h3>
A function can be defined as a mathematical expression which is used to define and represent the relationship that exists between two or more variables.
<h3>The types of function.</h3>
In Mathematics, there are different types of functions and these include the following;
- Piece-wise defined function.
For this exercise, we would indicate whether or not each of the above mathematical relation represents a function:
- Yes, the height, h(t) of a ball t seconds after it's dropped from the third floor of a building is a function.
- No, table B is not a function because no function can have the same y-values (5) for different x-values (1 and 8).
- Yes, table C is a function because it has different y-values for same x-values.
- Yes, graph D is a function because it has different y-values for same x-values.
In conclusion, we can infer and logically deduce that a function maps every x-value in a valid domain to a single y-value only.
Read more on domain here: brainly.com/question/17003159
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Answer:
3053.63m³
Step-by-step explanation:
use a calculator, not brainly
The answer is "B" I just looked at a calculator
The length of the hypotenuse is 15 feet.
Explanation
9 x 9+12
81+144
225/2
15
When we say that a function is continuous between x = -3 and x = 0 it means that it exists for all values of x in between -3 and 0. Let's take a look at each choice individually:
A: f(x) = (-x + 1)/(x + 2)
Now we don't actually need to know what the graph of this function looks like to see which values it is continuous for, instead we should look at which values of x will make this function undefined - in this case that would be x = -2. The reasoning behind this is that a number divided by 0 would be undefined, so when we search for which value of x would make the denominator of the equation 0, we get:
x + 2 = 0
x = -2
Since x = -2 is within the interval [-3, 0] we cannot say the function is continuous over this interval
B: f(x) = -2/(x + 1)
Using the same method as above we get:
x + 1 = 0
x = -1
x = -1 is again within the interval [-3, 0] and so the function is not continuous within this interval
C: f(x) = 3x/(x - 2)
x - 2 = 0
x = 2
x = 2 is outside the interval of [-3, 0] and so the function is continuous within this interval and C is the correct answer.
Just for the sake of it however we can look at D as well:
D: f(x) = 1/(2x + 1)
2x + 1 = 0
x = -1/2
-1/2 is within [-3, 0] and so D is not continuous over this interval
