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Likurg_2 [28]
3 years ago
7

Write an equivalent

Mathematics
1 answer:
erma4kov [3.2K]3 years ago
3 0

Answer:

By substituting the value of the variable and simplifying it with the equation you get 158.

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Bob's age is 4 times greater than Susanne's age. Dakota is three years younger than Susanne. The sum of Bob's, Susanne's, and Da
belka [17]
Susanne is 16 years old.

b = Bob's age

s = Susanne's age

d = Dakota's age

Bob's age is 4 times greater than Susanne's age:

b = 4s

Dakota is three years younger than Susanne:

d = s - 3

The sum of Bob's, Susanne's, and Dakota's ages is 93:

b + s + d = 93


 solve these equations:

b = 4s

d = s - 3

b + s + d = 93


and get:

b = 64 years

s = 16 years

(remember that s = Susanne) 

d = 13 years
5 0
3 years ago
X-3/2=x+8/6 solve the proportion
Aneli [31]

Answer:

x = 17/2

Step-by-step explanation:

x-3        x+8

------ = ------------

2               6

Using cross products

(x-3) *6 = 2 (x+8)

Distribute

6x - 18 = 2x+16

Subtract 2x from each side

6x-2x-18 = 2x-2x+16

4x-18 = 16

Add 18 to each side

4x-18+18 = 16+18

4x = 34

Divide each side by 4

4x/4 = 34/4

x = 17/2

8 0
3 years ago
Find the present balance.
Triss [41]
<h3>Credited balance:-</h3>

\\ \rm\longmapsto 115.90+115.90+345.85

\\ \rm\longmapsto 231.80+345.85

\\ \rm\longmapsto 577.65

<h3>Debited amount:-</h3>

\\ \rm\longmapsto 25.85+2.00

\\ \rm\longmapsto 27.85

<h3>Checked amount:-</h3>

\\ \rm\longmapsto 19.45+21.02+95.98

\\ \rm\longmapsto 117+19.45

\\ \rm\longmapsto 136.45

<h3>Total change in balance</h3>

\\ \rm\longmapsto 577.65-(27.85+136.45)

\\ \rm\longmapsto 577.65-191.3

\\ \rm\longmapsto 386.35

Now

<h3>Current balance</h3>

\\ \rm\longmapsto 386.35+271.31

\\ \rm\longmapsto\$ 657.66

8 0
2 years ago
Write the fraction 7/33 as a decimal.
timama [110]
 7/33 as a decimal is <span>0.21212121212</span>
7 0
2 years ago
Read 2 more answers
Please help me I don’t understand!!!
horrorfan [7]

Answer:

AGAIN DONT FORGET THE X

it would be "y=-4/5x+3"

Step-by-step explanation:

4 0
2 years ago
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