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alexandr402 [8]
3 years ago
8

40.An instrument that is inconsistent in measuring a variable would lack: trustworthiness credibility triangulation reliability

Mathematics
1 answer:
Alla [95]3 years ago
3 0

Answer: Reliability

Explanation: Reliability is the term that is used in the field of the tool which defines the consistency of the  variables and the results. It assures that the readings of the valuers that are obtained can be repeated in future experiments or study. It is also known as the dependability.

Other options are incorrect because trustworthiness and credibility are referred as the validity of the collected values and triangulation is known for tracking.Thus, the correct option is reliability

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Mary has g+24.50 in her bank account. bobby has 7g- 52.34 in his bank account. How much do they have in all?
vova2212 [387]
Combine:

<span>g+24.50  

</span><span>7g- 52.34 
---------------
8g - 27.84             <= answer</span>
5 0
3 years ago
What is the volume of a shape that has 13h,13l and 10w
creativ13 [48]

Answer:

<em>1690</em>

Step-by-step explanation:

V = LWH

V = 13 * 10 * 13

V = 1690

8 0
3 years ago
PLZ HELP ME! Whoever gets it right will be marked brainiest
Brut [27]

Answer:

Probability that Hannah only has to buy 3 or less boxes before getting a prize is 0.784

Step-by-step explanation:

Given, 40% of cereal boxes contain a prize

⇒probability of getting a prize on opening a box, P(A)=0.4

where A is the event of getting a prize on opening a cereal box

and probability of not getting a prize on opening a box, P(A')=1-P(A)=0.6

where A' is the event of not getting a prize on opening a cereal box

This problem needs to be divided into 3 situation:

  • Case 1, Where Hannah gets prize when she buys the first box:

Let K be the event of Hannah winning the prize on buying the first box.

⇒P(K)=P(A)=0.4

  • Case 2, Where Hannah gets prize when she buys the second box:

I<u>n this event Hannah should not get the prize in first box but should get the prize on buying the second box</u>

Let L be the event of Hannah winning the prize on buying the second box

So, P(L)=P(A')·P(A)

           =(0.6)·(0.4)

           =0.24

  • Case 3,Where Hannah gets prize when she buys the third box:

<u>In this event Hannah should not get the prize in first and second box but should get the prize on buying the third box</u>

Let L be the event of Hannah winning the prize on buying the third box

So, P(L)=P(A')·P(A')·P(A)

           =(0.6)·(0.6)·(0.4)

           =0.144

Let N be the event of Hannah winning the prize on buying 3 or less boxes before getting a prize

⇒N=K∪L∪M

Now, Required probability is P(N)=P(K∪L∪M)=P(K)+P(L)+P(M) [As events K,L and M are independent and disjoint events]

⇒P(N)=0.4+0.24+0.144

         =0.784

7 0
3 years ago
Charmaine is fertilizing her garden. The garden is in the shape of a rectangle. Its length is 12 feet and its width is 10 feet.
Nana76 [90]

Answer:

4 bags

Step-by-step explanation:

lxw

12x10=120

30x4=120

l=length

w=width

6 0
2 years ago
Can someone please help me​
astra-53 [7]

Answer:

square 20 has 44 green squares

square 21 has 45 green squares

Step-by-step explanation:

To solve the problem, we need to observe the cases, and determine/define a rule for each case (odd number of sides, or even number of sides).

For square one, we note that the centre square is shared by two diagonals, so we saved one square from the two diagonals.

The side length is 3 for square 1, 4 for square 2, and so on.

Let

n= square number (1, 2,3...)

L = side length (3,4,5...)

G1(n) = function that gives the number of green squares for square n, n=odd

G2(n) = function that gives the number of green squares for square n, n=even

side length, L=n+2   ................(1)

G1(n) = twice the side length less one, as discussed above

G1(n) = 2L-1       now substitute L=n+2

G1(n) = 2(n+2) -1    simplify

G1(n) = 2n + 3

Check:

for n=1, square 1 has 2*1+3 = 5 green squares ... checks

for n=3, square 3 has 2*3+3 = 9... checks

for n=5, square 5 has 2*5+3 = 13 ....checks

For even squares, it is even easier, because

G2(n) = 2L = 2(n+2)

check:

for n=2, square 2 has 2(2+2) = 8 green squares........checks

for n=4, square 4 has 2(4+2) = 12 green squares........checks.

Fincally, we apply our formula to n=20 and n=21

square 20 : G2(20) = 2(n+2) = 2(20+2) = 44 green quars

square 21 : G1(21) = 2n+3 = 2(21)+3 = 45 green squares

5 0
2 years ago
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