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AleksandrR [38]
3 years ago
11

HELP HELP HELP HELP HELP​

Mathematics
1 answer:
Anuta_ua [19.1K]3 years ago
7 0

Answer:

Length of base (a) = 5 units

Total Surface Area of Pyramid (T.S.A.) = ?

Now,

T.S.A. = Area of four triangles + Area of base

         = 4(\frac{\sqrt{3} }{4})(5^{2}) + 5^{2} = 25\sqrt{3}  + 25 ≈ 68.301sq. units

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Answer:

x = 8

Step-by-step explanation:

3 (x - 5) + 7x = 65

3x - 15 + 7x = 65

10x - 15 = 65

10x = 80

x = 8

5 0
2 years ago
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Find the midpoint of the line segment with the endpoints (1, 0) and (2, -10).
Mariulka [41]

Answer:

\bigl(\frac{3}{2},-5\bigr)

or in decimal form

(1.5,-5)

Step-by-step explanation:

The midpoint of the line with endpoints (x_1,y_1) and (x_2,y_2) is \bigl(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}\bigr). just take the average between the points

so given the points (1,0) and (2,-10)

x_1=1

y_1=0

x_2=2

y_2=-10

the midpoint is found as follows:

\bigl(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}\bigr)

\bigl(\frac{1+2}{2},\frac{0-10}{2}\bigr)

\bigl(\frac{3}{2},\frac{-10}{2}\bigr)

\bigl(\frac{3}{2},-5\bigr)

or in decimal form

(1.5,-5)

7 0
3 years ago
The volume of water remaining in a hot tub when it is being drained satisfies the differential equation dV/dt = −3(V)^1/2 , wher
dimaraw [331]
The given function is a variable separable differential equation. Combine like terms, integrate, apply the appropriate limits, and express V in terms of t. This is done as follows:

dV/dt = -3(V)^1/2
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m here is the initial V which is 225. Then after integrating,

-2/3 (√V - √225) = t
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V= \sqrt{ \frac{-3}{2}t+15 }

That is the expression for V at time t. I hope I was able to help. Have a good day.
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Both families use 1250 kWh for the given 30 day period. The Freeman family uses 400 kWh during on-peak hours and 850 during off-
Natalka [10]
Ok ummm I honestly don’t know I’m so sorry I couldn’t help you wit this prob
8 0
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Help, i just need the answers and no need for explanations.
maria [59]

Answer:

The equation of the quadratic function shown is;

x^2+ 2x -3

Step-by-step explanation:

Here in this question, we need to know the quadratic equation whose graph was shown.

The key to answering this lies in knowing the roots of the equation.

The roots of the equation are the solution to the quadratic equation and can be seen from the graph at the point where the quadratic equation crosses the x-axis.

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These are at the points x = -3 and x = 1

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3 years ago
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