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Solve the inequality 10(z + 3) ≥ 10z + 19
1 answer:
<u>Question: Solve the inequality 10(z + 3) ≥ 10z + 19.</u>
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<em>Answer:</em> <em>The answer to your question is "All Real Numbers". Please see the attachment below for all the steps provided. Since 0≥-11, this means that, "All Real Numbers; [Numbers greater or equal to 1] are going to be greater than -11. Thus, meaning that the answer is </em><em>All Real Numbers.</em>
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Answer: (7, 20)
Concept:
There are three general ways to solve systems of equations:
- Elimination
- Substitution
- Graphing
Since the question has specific requirements, we are going to use <u>substitution </u>to solve the equations.
Solve:
<u>Given equations</u>
y = 3x - 1
2x + 6 = y
<u>Substitute the y value since both equations has isolated [y]</u>
2x + 6 = 3x - 1
<u>Add 1 on both sides</u>
2x + 6 + 1 = 3x - 1 + 1
2x + 7 = 3x
<u>Subtract 2x on both sides</u>
2x + 7 - 2x = 3x - 2x
<u>Find the value of y</u>
y = 3x - 1
y = 3(7) - 1
y = 21 - 1
Hope this helps!! :)
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