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vovangra [49]
3 years ago
15

Solve the inequality 10(z + 3) ≥ 10z + 19

Mathematics
1 answer:
fredd [130]3 years ago
5 0

<u>Question: Solve the inequality 10(z + 3) ≥ 10z + 19.</u>

<u />

<em>Answer:</em>  <em>The answer to your question is "All Real Numbers". Please see the attachment below for all the steps provided. Since 0≥-11, this means that, "All Real Numbers; [Numbers greater or equal to 1] are going to be greater than -11. Thus, meaning that the answer is </em><em>All Real Numbers.</em>

<em />

<em>Feedback: Please give me a heart or mark us as the brainliest of this question! If you need any further help, please feel free to leave a comment to this answer or message me on instagram: @jessmyybest</em>

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Choose all the numbers that are common multiples of 3 and 12.
spayn [35]
<h3>Answers: 48 and 72</h3>

=========================================================

Explanation:

The number 12 is a multiple of 3 because 3*4 = 12.

So when looking for common multiples of 3 and 12, we simply need to look at multiples of 12.

The multiples of 12 are:

  • 12, 24, 36, 48, 60, 72, 84, 96, 120, ...

We see that 48 and 72 are on the list. The values 21, 27, 63, 81 are not on the list, so cross them out.

Now we could keep that list of multiples going to see if 844 is on there or not. A better method is to divide 844 over 12. If we get a whole number, then it's a multiple of 12.

844/12 = 70.333 approximately.

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Only 48 and 72 are multiples of 12 (and also multiples of 3).

6 0
2 years ago
4−(−8)= please help i need it now
s344n2d4d5 [400]

Answer:

hope it helps...

- multiplied with another - gives us a +.

While opening a bracket we consider a sign of multiplication. so the equation becomes 4 + 8 which gives us 12. Thus 12 is the answer.

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