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Alborosie
3 years ago
8

Write 9^0,9^3,and 9^-2 in order from least to greatest

Mathematics
2 answers:
DiKsa [7]3 years ago
5 0

Answer:

Correct order : 9^{-2},9^0\text{ and }9^3.

Step-by-step explanation:

Rule: If a^x and a^y are two numbers and a>1, then a^x>a^y for all x>y.

The given numbers are

9^0,9^3\text{ and }9^{-2}

It these numbers base are same, i.e., 9 which is great than 1.

We know that

-2

Using the above rule we get

9^{-2}

0.012345679

Hence, the correct order from least to greatest is 9^{-2},9^0\text{ and }9^3.

stellarik [79]3 years ago
4 0
9^-2,9^0,9^3 and that is the answer
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