Question

Write 9^0,9^3,and 9^-2 in order from least to greatest

Answer 1

Answer:

Correct order : $9^{-2},9^0\text{ and }9^3$.

Step-by-step explanation:

Rule: If $a^x$ and $a^y$ are two numbers and a>1, then $a^x>a^y$ for all $x>y$.

The given numbers are

$9^0,9^3\text{ and }9^{-2}$

It these numbers base are same, i.e., 9 which is great than 1.

We know that

$-2$

Using the above rule we get

$9^{-2}$

$0.012345679$

Hence, the correct order from least to greatest is $9^{-2},9^0\text{ and }9^3$.

Answer 2

9^-2,9^0,9^3 and that is the answer