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Kaylis [27]
3 years ago
9

What the answer now to the question

Mathematics
1 answer:
Lostsunrise [7]3 years ago
8 0

Step-by-step explanation:

<em>Hello</em><em>!</em><em>!</em><em>!</em>

<em>Given</em><em>, </em><em> </em><em>VXW</em><em> </em><em>is</em><em> </em><em>a</em><em> </em><em>Right angled triangle</em><em> </em><em>where</em><em> </em><em>WV</em><em> </em><em>=</em><em>4</em><em> </em><em>and</em><em> </em><em>XV</em><em> </em><em>=</em><em>5</em><em>.</em>

<em>now</em><em>,</em><em> </em><em>b</em><em>y</em><em> </em><em>taking</em><em> </em><em>reference angle</em><em> </em><em>as angle </em><em>W</em><em>,</em><em> </em><em>and</em><em> </em><em>using</em><em> </em><em>tangent</em><em> </em><em>we</em><em> </em><em>get</em><em>;</em>

<em>p</em><em>=</em><em>5</em>

<em>b</em><em>=</em><em>4</em>

<em>again</em><em>, </em>

<em>tan</em><em> </em><em>thita</em><em> </em><em>=</em><em>p</em><em>/</em><em>b</em>

<em>tan</em><em> </em><em>thita</em><em> </em><em>=</em><em> </em><em>5</em><em>/</em><em>4</em>

<em>so</em><em>,</em><em> </em><em>tan</em><em> </em><em>thita</em><em> </em><em>=</em><em>1</em><em>.</em><em>2</em><em>5</em><em>.</em>

<em>now</em><em>,</em><em> </em><em>to</em><em> </em><em>find</em><em> </em><em>angle</em><em> </em><em>W</em><em>,</em><em> </em><em>we</em><em> </em><em>should</em><em> </em><em>d</em><em>o</em><em> </em><em>tan</em><em> </em><em>thita</em><em> </em><em>inverse</em><em>;</em>

<em>or</em><em>,</em><em> </em><em>(</em><em>tan</em><em> </em><em>thita</em><em>)</em><em>-1</em><em>=</em><em> </em><em>tan</em><em> </em><em>thita</em><em>-1</em><em>(</em><em>1</em><em>.</em><em>2</em><em>5</em><em>)</em>

<em>or</em><em>,</em><em> </em><em>(</em><em>tan</em><em> </em><em>thita</em><em>)</em><em> </em><em>-1</em><em> </em><em>=</em><em>5</em><em>1</em><em>.</em><em>3</em><em>4</em><em>0</em><em>1</em><em>°</em><em>.</em>

<em>Now</em><em>,</em><em> </em><em>by</em><em> </em><em>rounding</em><em> </em><em>off</em><em> </em><em>we</em><em> </em><em>get</em><em>,</em>

<em>tan</em><em> </em><em>thita</em><em> </em><em>(</em><em>angle</em><em> </em><em>W</em><em> </em><em>)</em><em>=</em><em> </em><em>5</em><em>1</em><em>°</em><em>.</em>

<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

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vekshin1
16 gal = 200 mi
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5600/28

X = 28
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Step-by-step explanation:

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A triangle with an area of 37 units? is dilated by a scale factor of . Find the area of
sergeinik [125]

Answer:

<u>58 units</u>

Step-by-step explanation:

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Find the common fraction equivalent to 0.12
jonny [76]
The answer is:  " \frac{4}{33} "  .
______________________________
Given:  0.1212121212..... repeating ;  write that value as a fraction;
______________________________________________________
In other words; we are given:  "0.1212121212..... repeating infinitely" ;  

→ that is to say; "0.12 ...  ;  {the "12" decimal portion repeats infinitely} ; 
_______________________________________________________
→ We write this value, as a fraction, as:  "12/99" ;
__________________________________________
→Explanation:
__________________________________________ 


Note:  "0.99999999...... repeating infinitely;  =  "1" .
_________________________________________
→Since:

Let us say that we have: 

"x = 0.999999 ; repeating infinitely;  

In order words, let us say we have: "x = 0.9.... ;  the "9" decimal repeats infinitely; 
_____________________________________________________
   Then "10x" ;  (that is: "10" multlipled by "x";  or "10*x" or "10x" );  is equal to:

"10" * (0.999999.....)  = 9.99999999...... (the "9" decimal repeats infinitely);

in other words:  10x = 9.99999999....

Divide each side by "10" ;

to get "x = 0.9999999....." ; the decimal "9" repeats indefinitely...." ;

But if you have:  "10x = 10" ;  divide each side of the equation by "10" ; 
   you get: "x = 1" . 
____________________
Also,  if "x = 0.9999...(repeating infinitely); 

then:  10x = 9.99999.
_______________________________________________
           10x  =  9.999999999999999......
       −     x  =  0.999999999999999.......
    _____________________________________
            9x  =  9.00000000000000000000.....

 →  9x = 9 ; 

Divide each side of the equation; to get; 

 9x /9 = 9/ 9 ;  to get:  x = 1 ; and we have: x = 0.9999.... ;  so
  x= 0.99999.... = 1 ; 
__________________________________________________
So, if the numbers "12" is repeating, we divie "12" by "99" ; 
  that is; we divide "12" by "two 9's" ;  since "12" is a "TWO-digit number"; a "two-digit number" is being repeated infinitely.
________________________________________
            So;  0.12121212.....(the "12" is the decimal that repeats infinitely);            
                   
=  12/99 ;  which can be simplified;

Divide each side (both the numerator AND the denominator); by "3" ;
_________________________________________
  " 12/99 "  =  "(12÷3) / (99÷3) = 4/33 " .
_________________________________________
The answer is:  \frac{4}{33}  .
_________________________________________
8 0
3 years ago
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