A geometric sequence has a first term of 3 and a fourth term of 81÷8.
Find the eighth term
1 answer:
Answer:
6561 / 128
Step-by-step explanation:
The nth term of a geometric sequence is:
a = a₁ (r)ⁿ⁻¹
The first term is 3, and the fourth term is 81/8.
81/8 = 3 (r)⁴⁻¹
27/8 = r³
r = 3/2
The eighth term is therefore:
a = 3 (3/2)⁸⁻¹
a = 6561 / 128
You might be interested in
Circumference of a circle is 2(pi)(r)
2(3.14)(7)= 43.96
So the answer is B
Step-by-step explanation:
dilatation with scale factor (k) = 2
the answer is Probably C.
