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3 years ago

Dave wants to estimate how many pounds of dog food his dogs eat in one year.

Mathematics

2 answers:

nadya68 [22]3 years ago

8 0

12 x d=
12= how many months there are
d= pounds in each dogfood bag

Verdich [7]3 years ago

3 0

Let us say the dog eats x pounds of dog food in one month.

There are 12 months in a year.

So applying unitary method:

Quantity of dog food required by dog in 12 months = 12x

Answer : The dog requires 12x pounds of dog food in a year.

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agasfer [191]

180- 124= 56

So 56 degrees

4 0

3 years ago

Read 2 more answers

Find two vectors in R2 with Euclidian Norm 1<br> whoseEuclidian inner product with (3,1) is zero.

alina1380 [7]

Answer:

$v_1=(\frac{1}{10},-\frac{3}{10})$

$v_2=(-\frac{1}{10},\frac{3}{10})$

Step-by-step explanation:

First we define two generic vectors in our $\mathbb{R}^2$ space:

$v_1 = (x_1,y_1)$
$v_2 = (x_2,y_2)$

By definition we know that Euclidean norm on an 2-dimensional Euclidean space $\mathbb{R}^2$ is:

$\left \| v \right \|= \sqrt{x^2+y^2}$

Also we know that the inner product in $\mathbb{R}^2$ space is defined as:

$v_1 \bullet v_2 = (x_1,y_1) \bullet(x_2,y_2)= x_1x_2+y_1y_2$

So as first condition we have that both two vectors have Euclidian Norm 1, that is:

$\left \| v_1 \right \|= \sqrt{x^2+y^2}=1$

and

$\left \| v_2 \right \|= \sqrt{x^2+y^2}=1$

As second condition we have that:

$v_1 \bullet (3,1) = (x_1,y_1) \bullet(3,1)= 3x_1+y_1=0$

$v_2 \bullet (3,1) = (x_2,y_2) \bullet(3,1)= 3x_2+y_2=0$

Which is the same:

$y_1=-3x_1\\y_2=-3x_2$

Replacing the second condition on the first condition we have:

$\sqrt{x_1^2+y_1^2}=1 \\\left | x_1^2+y_1^2 \right |=1 \\\left | x_1^2+(-3x_1)^2 \right |=1 \\\left | x_1^2+9x_1^2 \right |=1 \\\left | 10x_1^2 \right |=1 \\x_1^2= \frac{1}{10}$

Since $x_1^2= \frac{1}{10}$ we have two posible solutions, $x_1=\frac{1}{10}$ or $x_1=-\frac{1}{10}$ . If we choose $x_1=\frac{1}{10}$ , we can choose next the other solution for $x_2$ .

Remembering,

$y_1=-3x_1\\y_2=-3x_2$

The two vectors we are looking for are:

$v_1=(\frac{1}{10},-\frac{3}{10})\\v_2=(-\frac{1}{10},\frac{3}{10})$

5 0

2 years ago

ITS DUE TODAY HELP PLS Which steps would be used to solve this equation? Check all that apply. Multiply by 3 on both sides of th

kumpel [21]

Answer:

Multiply by 3 on both sides of the equation.

2.78 × 3 = 8.34, so t = 8.34.

Substitute 8.34 for t to check the solution.

Step-by-step explanation:

To solve the equation = 2.78

we will use the steps below to solve this equation;

First, multiply by 3 on both-side of the equation. That is;

× 3= 2.78 × 3

On the left hand side of the equation 3 will cancel-out 3, leaving us with just t while 3 will be multiply by 2.77 on the right-hand side of the equation to give 8.34

t = 8.34

we can further substitute 8.34 for t to check the correctness of the solution

that is;

= 2.78

5 0

3 years ago

I need help please answer quick!

Mazyrski [523]

Answer:

3in. is the answer

doooo itttt fassstttt

mark it as brInlist

3 0

2 years ago

hello like almost everyone else on here, I'm probably gonna fail so uh help, please? In your own words explain how to multiply/d

babymother [125]

Answer: It does not matter whether you multiply the radicands or simplify each radical first. You multiply radical expressions that contain variables in the same manner. As long as the roots of the radical expressions are the same, you can use the Product Raised to a Power Rule to multiply and simplify.

Step-by-step explanation:

3 0

2 years ago