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Brut [27]
3 years ago
11

Dave wants to estimate how many pounds of dog food his dogs eat in one year.

Mathematics
2 answers:
nadya68 [22]3 years ago
8 0
12 x d=
12= how many months there are
d= pounds in each dogfood bag
Verdich [7]3 years ago
3 0

Let us say the dog eats x pounds of dog food in one month.

There are 12 months in a year.

So applying unitary method:

Quantity of dog food required by dog in 12 months = 12x

Answer : The dog requires 12x pounds of dog food in a year.

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Let f(x)=9x-2 and g(x)=-x+3. find f(g(x)).
ruslelena [56]
f(g(x))=9(-x+3)-2 \\ f(g(x))= -9x+27-2 \\ f(g(x))= -9x+25
8 0
3 years ago
Read 2 more answers
Indica and jean begin their hike at 10 am. they plan to hike fromthe 2.4 mile marker to the 8.1 mile marker. they plan to hike a
Murrr4er [49]
Yes they should reach the 8.1 mile marker by noon
2 hours equals 6 miles 2.4+6=8.4
if they kept walking for a full 2 hours they would reach the 8.4 mile marker
8 0
3 years ago
Factor completely. y2+6y+8
zloy xaker [14]
If you can't see the picture the answer is: (y+4)(y+2).

Hope this helps, and May the Force Be With You!
-Jabba

4 0
3 years ago
Read 2 more answers
What is the Median for the following set of numbers? ​21 23 76 47 55 135 45 30 17
Leno4ka [110]

Answer:

Median = 45

Step-by-step explanation:

We are given the following data set:

21, 23, 76, 47, 55, 135, 45, 30, 17

Median is the number that divides the data into two equal parts.

Formula:

Median:\\\text{If n is odd, then}\\\\Median = \displaystyle\frac{n+1}{2}th ~term \\\\\text{If n is even, then}\\\\Median = \displaystyle\frac{\frac{n}{2}th~term + (\frac{n}{2}+1)th~term}{2}

Sorted data:

17, 21, 23, 30, 45, 47, 55, 76, 135

Sample size = 9, which is odd

Median =

\dfrac{9+1}{2}^{th}\text{ term} = \dfrac{10}{2}^{th}\text{ term} = 5^{th}\text{ term}\\\\= 45

The median of given set of numbers is 45.

7 0
3 years ago
921 divided by 2 what’d the remainder
s2008m [1.1K]
921÷ 2 = 460.5
which means the remainder is 1
So; the answer is 1
8 0
3 years ago
Read 2 more answers
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