Question

if a line crosses the y-axis at (0, 1) and has a slope of `4/5`, what is the equation of the line? A. 4y − 5x = 5 B. y − 4x = 5 C. 5y + 4x = 5 D. 5y − 4x = 5

Answer 1

Answer:

option (d) is correct.

if a line crosses the y-axis at (0, 1) and has a slope of $\frac{4}{5}$, then equation  of line is 5y - 4x = 5.

Step-by-step explanation:

Given : if a line crosses the y-axis at (0, 1) and has a slope of $\frac{4}{5}$.

We need to find the equation of line.

Equation of line is of the form y = mx + c, where m is the slope of line and c is the y- intercept. that is the point where line meets y- axis.

Given y intercept at (0, 1 ) ⇒ c = 1

Also, slope m = $\frac{4}{5}$

Substitute it in equation,  we get ,

y = mx + c ⇒  $y=\frac{4}{5}x+1$

Solving , we get equation of line as ,

5y = 4x + 5 ⇒ 5y - 4x = 5

Thus, option (d) is correct.

if a line crosses the y-axis at (0, 1) and has a slope of $\frac{4}{5}$, then equation  of line is 5y - 4x = 5.

Answer 2

Answer:

Choice D is correct answer.

Step-by-step explanation:

From question statement, we observe that

Slope is given and  a point is given .

slope =  4/5   and point is (0,1)

y = mx+c is equation of line where m is slope and c is y-intercept.

y-intercept is a point where the value of x is zero.

hence, y-intercept = c = 1

Putting the given values in formula, we have

y = (4/5)x+1

y =( 4x+5) / 5

5y = 4x+5

Adding -4x to both sides of above equations, we have

5y-4x = 4x+5-4x

5y-4x = 5 is equation of line that crosses the y-axis at (0,1) and has a slope of 4/5.