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4 years ago

Choose a random number

Mathematics

1 answer:

Andre45 [30]4 years ago

4 0

Answer:

12/25 or 48% or 0.48

Step-by-step explanation:

There are 12 even numbers.

25 is good for percentages because you can just multiply it by four to get to 100

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Help me, please! It's due tomorrow!

anyanavicka [17]

Answer:

m=y2-y1 / x2-x1

m=15-20 / 1-0

m=-5 / 1

m=-5

y=mx+b

20=-5*0+b

20=0+b

20=b

y=-5x+20

8 0

3 years ago

3x (9-6) +(2x3)=<br> i dont understand this

mojhsa [17]

Answer:

2x^3 + 9 (if you meant the x to be multiplication)

2x^3 + 9x (if you meant the x to be a variable)

Step-by-step explanation:

Hope this helps!

brainliest?

(::)

8 0

3 years ago

What is a solution to the equation 3 / m + 3 - M / 3 - M equals m^2 + 9 / m^2-9?

Mnenie [13.5K]

Answer: Last option.

Step-by-step explanation:

Given the equation:

$\frac{3}{m+3}-\frac{m}{3-m}=\frac{m^2+9}{m^2-9}$

Follow these steps to solve it:

- Subtract the fractions on the left side of the equation:

$\frac{3(3-m)-m(m+3)}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}\\\\\frac{9-3m-m^2-3m}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}\\\\\frac{-m^2-6m+9}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}$

- Using the Difference of squares formula ( $a^2-b^2=(a+b)(a-b)$ ) we can simplify the denominator of the right side of the equation:

$\frac{-m^2-6m+9}{(m+3)(3-m)}=\frac{m^2+9}{(m+3)(m-3)}$

- Multiply both sides of the equation by $(m+3)(3-m)$ and simplify:

$\frac{(-m^2-6m+9)(m+3)(3-m)}{(m+3)(3-m)}=\frac{(m^2+9)(m+3)(3-m)}{(m+3)(m-3)}\\\\-m^2-6m+9=\frac{(m^2+9)(3-m)}{(m-3)}$

- Multiply both sides by $m-3$ :

$(-m^2-6m+9)(m-3)=\frac{(m^2+9)(3-m)(m-3)}{(m-3)}\\\\(-m^2-6m+9)(m-3)=(m^2+9)(3-m)$

- Apply Distributive property and simplify:

$(-m^2-6m+9)(m-3)=(m^2+9)(3-m)\\\\-m^3-6m^2+9m+3m^2+18m-27=3m^2+27-m^3-9m\\\\-m^3-3m^2+27m-27+m^3-3m^2+9m-27=0\\\\-6m^2+36m-54=0$

- Divide both sides of the equation by -6:

$\frac{-6m^2+36m-54}{-6}=\frac{0}{-6}\\\\m^2-6m+9=0$

- Factor the equation and solve for "m":

$(m-3)^2=0\\\\m=3$

In order to verify it, you must substitute $m=3$ into the equation and solve it:

$\frac{3}{3+3}-\frac{3}{3-3}=\frac{3^2+9}{3^2-9}\\\\\frac{3}{6}-\frac{3}{0}=\frac{18}{0}$

<em>NO SOLUTION</em>

7 0

3 years ago

Hey does any body know how i can approximate 13 like this had this homework but it got late on me.

Illusion [34]

Answer:

(see attachment)

To approximate the square root of 13:

Working from the top down...

Enter the number you are trying to approximate in the top box: $\boxed{\sf \sqrt{13}}$

Find the perfect squares directly below and above 13.

Perfect squares: 1, 4, 9, 16, 25, 36, ...

Therefore, the perfect squares below and above 13 are: 9 and 16

Enter these with square root signs in the next two boxes: $\boxed{\sf \sqrt{9}}$ and $\boxed{\sf \sqrt{16}}$

Carry out the operation and enter $\boxed{\sf 3}$ and $\boxed{\sf 4}$ in the next two boxes.

Enter the number you are trying to square root (13) in the top left box, the perfect square above it (16) in the box below, then the perfect square below it (9) in the two boxes to the right of these. Carry out the subtractions and place the numbers in the boxes to the right.

$\dfrac{\boxed{\sf 13}-\boxed{\sf 9}}{\boxed{\sf 16}-\boxed{\sf 9}}=\dfrac{\boxed{\sf 4}}{\boxed{\sf 7}}$

Now enter the number you are trying to square root (13) under the square root sign. Place the square root of the perfect square below it (3) in the box to the right. Copy the fraction from above (4/7). Finally, enter this mixed number into a calculator and round to the nearest hundredth.

$\sf \sqrt{13}=\boxed{\sf3}\dfrac{\boxed{\sf 4}}{\boxed{\sf 7}}=\boxed{\sf3.57}$

7 0

2 years ago

A professor let's his students pick 3 out of 8 assignments to complete. How many combinations of the 3 assignments are possible

sertanlavr [38]

It is indeed justifiable that the operation involved in this task is combination because the arrangement of the assignments are not important. The combination may be solved directly from a scientific calculator using the function,
nCr
where in this item the value of n is 8 and that of r is 3. Substituting and solving the combination,
8C3 = 56
Therefore, there are exactly 56 combinations possible.

5 0

4 years ago

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